Answer:
x = (-27)/11
Step-by-step explanation:
Solve for x:
(-11 x)/54 - 1/2 = 0
Put each term in (-11 x)/54 - 1/2 over the common denominator 54: (-11 x)/54 - 1/2 = (-27)/54 - (11 x)/54:
(-27)/54 - (11 x)/54 = 0
(-27)/54 - (11 x)/54 = (-11 x - 27)/54:
(-11 x - 27)/54 = 0
Multiply both sides of (-11 x - 27)/54 = 0 by 54:
(54 (-11 x - 27))/54 = 54×0
(54 (-11 x - 27))/54 = 54/54×(-11 x - 27) = -11 x - 27:
-11 x - 27 = 54×0
0×54 = 0:
-11 x - 27 = 0
Add 27 to both sides:
(27 - 27) - 11 x = 27
27 - 27 = 0:
-11 x = 27
Divide both sides of -11 x = 27 by -11:
(-11 x)/(-11) = 27/(-11)
(-11)/(-11) = 1:
x = 27/(-11)
Multiply numerator and denominator of 27/(-11) by -1:
Answer:x = (-27)/11
Answer:
Ray : Line NA, Line NB, Line AB
Vertex : Vertex N
Angle: Angle ANB
Parallel Lines: None
Coplanar Points: Points C, A, F, N, B
Collinear Points: Points A, N, B
Segment Addition Postulate: AN + NB = AB
Perpendicular Lines: None
Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Well they both have integers in it there the same thing except your adding and subtracting. <span>Subtraction is the same thing as adding the opposite of the number. </span>
Answer:
3
Step-by-step explanation:
equation, y=3x, because when x is 1, y is 3, so the equation is y=3x, and the slope is equal to how much of x is equal to y, so 3
Pls brainliest
