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Butoxors [25]
2 years ago
6

PLEASE HELP ASAP WILL GIVE BRAINLEIST!!

Mathematics
1 answer:
melisa1 [442]2 years ago
5 0

Answer:

c

Step-by-step explanation:

the answer is 201.6 but c is the closest

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Bonnie withdrew $1,200 from her savings account. She spent 1/5 of the money on travel arrangements. She spent 2/3 of the remaini
svetoff [14.1K]
Withdrew 1200
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leaving her with : 1200 - 240 = 960
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leaving her with : 960 - 640 = 320
320 - lunch = 300.50
320 - 300.50 = lunch
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3 years ago
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You plant a garden in the shape of a triangle as shown in the figure. What is the perimeter of the garden? Find the values of x
Vadim26 [7]

Answer:

x = 42°

y = 69°

Step-by-step explanation:

From the picture attached,

Given triangle is an isosceles triangle.

Therefore, two sides will be equal and measure 8 yd.

Measure of 3rd side of the triangle = 6 yd

Perimeter of the garden = 8 + 8 + 6

                                        = 22 yd

In an isosceles triangle, opposite angles of the equal sides will be equal.

Therefore, y = 69°

By the property of interior angles of a triangle,

x° + y° + 69° = 180°

x° + 69° + 69° = 180°

x = 180 - 138

x = 42°

7 0
3 years ago
What is the unit rate of $120 15 books
Svetlanka [38]
I think its 8? someone correct me if im wrong.


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3 years ago
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M is the midpoint of AN, A has coordinates
maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

8 0
3 years ago
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