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Bezzdna [24]
3 years ago
10

#4. Find the missing angle measures

Mathematics
2 answers:
baherus [9]3 years ago
4 0

Answer:

Step-by-step explanation:

x = 55

x + 55 = 110

x + 20 = 75

x + 65 = 120

liubo4ka [24]3 years ago
4 0

Answer:

x°=130°

The sum of two opposite angles in a quadrilateral is 180

⇒x+55°+x+65°=180°

⇒2x+120°=180°

⇒2x=60°

⇒x=30°

Có x+20 °+x°=180°

⇒30°+20°+x°=180°

⇒x°=130°

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What is 3 3/9 as a decimal
Sophie [7]

Answer:

3.3333333333

Step-by-step explanation:

3 3/9 --> 10/3

10 (dived by) 3=3.3333333333

8 0
4 years ago
Read 2 more answers
Find the area of the trapezoid with bases 12 cm and 14 cm and height 9 cm
Cerrena [4.2K]

Answer:

117

Step-by-step explanation:

b1+b2÷2×h is the formula.

Just fill in the formula with the numbers you have.

12+14=26

26÷2=13

13×9=117

3 0
3 years ago
How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement
jonny [76]

Answer: 152ft^2

The amount of material needed to construct the tent is 152ft^2

Step-by-step explanation:

The amount of material needed to construct a triangular tent= the surface area of the triangular tent.

S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.

S.A = Ab + At + Ar ....1

Area of the base Ab= Length × width = 8×6 = 48ft^2

Area of the two triangles At = 2 × 0.5 × width × height

At = width × height = 6×4 = 24ft^2

Area of the two rectangles Ar = 2 × side measurement × length

Side measurement is given as 5ft.

or it can be calculated using;

Side length can be calculated using Pythagoras theorem.

Examining the figure attached, we can see that;

Side breadth b = √(h^2 + (w/2)^2)

b = √(4^2 + (6/2)^2) = √(16+9) = √25

b = 5ft

Ar = 2×5×8 = 80ft^2

From eqn1, S.A can be solved as;

S.A = 48 + 24 + 80

S.A = 152ft^2

7 0
4 years ago
2(a³+b²+11)+1(3+a³+b+11)
Ann [662]

Answer:

2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

2(a^3+b^2+11)+1(3+a^3+b+11)

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14

Therefore, 2(a^3+b^2+11)+1(3+a^3+b+11) is equal to:

2a^3+2b^2+22+a^3+b+14

Now, combining like terms using the commutative property of addition, we get:

=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36

Therefore, the simplified form is 3a^3+2b^2+b+36

8 0
4 years ago
Hi! I would really appreciate it if you can help me with this problem.
miss Akunina [59]
GCF: 2v5
2v5(4v+1+5v4)
7 0
3 years ago
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