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3 years ago

Mg + 2HCl ⟶ MgCl2 + H2

Chemistry

1 answer:

Ivanshal [37]3 years ago

7 0

Answer: m = 24.31 g/mol · 1.13 mol

Explanation: 2 mol HCl use 1 mol Mg.

Magnesium is used 0.5 · 2.26 mol = 1.13 mol

M(Mg) = 24.31 g/ mol

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Explanation :

Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

The given unbalanced chemical reaction is,

$Fe(s)+I^-(aq)\rightarrow I_2(s)+Fe^{3+}(aq)$

Half reactions of oxidation and reduction are :

Oxidation : $Fe(s)\rightarrow Fe^{3+}+3e^-$ ......(1)

Reduction : $2I^-(aq)+2e^-\rightarrow I_2$ .......(2)

In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:

Oxidation : $2Fe(s)\rightarrow 2Fe^{3+}+6e^-$ ......(1)

Reduction : $6I^-(aq)+6e^-\rightarrow 3I_2$ .......(2)

The overall balanced chemical reaction will be:

$2Fe(s)+6I^-(aq)\rightarrow 3I_2(s)+2Fe^{3+}(aq)$

From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.

Hence, the correct option is, (C) 6

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