Use the formula for volume. V = lwh. Plug in the numbers for length, width, and height. Now we have V = 4.0 x 2.0 x 1.0, which is 8.0. So the volume of the block is 8.0 cm.
Thanks for your question! Don't forget to rate and give me the brainliest answer! Then, I can help you with all your problems! ^-^ ~
Answer:
C5H12.
Explanation:
The compound will be C5H12.
Now consider the general formula for the combustion of an alkane;
CnH2n+2 + 3n+1/2O2-----> nCO2 + (n+1) H2O
If we substitute n=5, we have;
C5H12 + 8O2-----> 5CO2 + 6H2O
Hence the answer above.
The question is incomplete, the complete question is;
When 1 mole of P4O10(s) reacts with H2O(l) to form H3PO4(aq) according to the following equation, 453 kJ of energy are evolved.
P4O10(s) + 6H2O(l)When 1 mole of P4O10(s) reacts4H3PO4(aq)
Is this reaction endothermic or exothermic? _________endothermicexothermic
Answer:
The reaction is exothermic
Explanation:
An exothermic reaction refers to any reaction in which heat was EVOLVED. The word was stressed to indicate that it holds the key to answering the question correctly.
We were told in the question that heat was evolved, hence the reaction is exothermic in nature.
The balanced thermochemical equation of the reaction is :
P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(aq) ____ ΔH = -453 kJ
Answer:
Neptunium, Protactinium, plutonium and more
Explanation:
Answer:
a) 1.71 × 10⁻³ M
b) 8.00 × 10⁻⁵ M
Explanation:
In order to calculate the solubility (S) of Pb(SCN)₂ we will use an ICE chart. We identify 3 stages (Initial, Change, Equilibrium) and complete each row with the concentration or change in the concentration.
Pb(SCN)₂(s) ⇄ Pb²⁺(aq) + 2 SCN⁻(aq)
I 0 0
C +S +2S
E S 2S
The solubility product (Ksp) is:
Ksp = 2.00 × 10⁻⁵ = [Pb²⁺].[SCN⁻]² = S . (2S)² = 4S³
S = 1.71 × 10⁻³ M
<em>b) Calculate the molar solubility of lead thiocyanate in 0.500 M KSCN.</em>
KSCN is a strong electrolyte that dissociates to give 0.500 M K⁺ and 0.500M SCN⁻.
Pb(SCN)₂(s) ⇄ Pb²⁺(aq) + 2 SCN⁻(aq)
I 0 0.500
C +S +2S
E S 0.500 + 2S
Ksp = 2.00 × 10⁻⁵ = [Pb²⁺].[SCN⁻]² = S . (0.500 + 2S)²
In the term (0.500 + 2S)², 2S is negligible.
Ksp = 2.00 × 10⁻⁵ = S . (0.500)²
S = 8.00 × 10⁻⁵ M
