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Bogdan [553]
2 years ago
10

Sam really wanted to buy a car, but did not have the money at the moment. He was talking to the salesman and they said that he c

ould get him a loan for the car for $30,000 on a 11.41% per year interest rate compounded continuously. He wanted to spend his money on other things so he held off on paying down the balance of the loan for a while. 1. What was the loan balance 3 months in? 2. Sam has a take home pay of $40,000 a year. What percentage of his take home pay is the interest on the loan in his first year?
Mathematics
1 answer:
wolverine [178]2 years ago
8 0

Answer:

1) $30,821  ( loan balance after 3 months in )

2) 8.56%

Step-by-step explanation:

Final Amount of  compound interest: A  = P ( 1 + i ) ^ n

p = principal = $30,000

r = interest rate = 11.41% = 0.1141

n = number of years

1) Loan balance after 3 months

n = 3/12 = 0.25 years

A = 30,000 ( 1 + 0.1141 ) ^ 0.25

   = $30,821  ( loan balance after 3 months in )

2) Loan Balance after 1 year

A = 30,000 ( 1 + 0.1141 ) ^ 1

  =  $33423

interest on loan = 33423 - 30,000 = $3423

percentage of $40,000 is $3423

= 3423 / 40,000 * 100

= 8.56%

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Subtract the following:

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B) 49 rupees 79 paise from 123 rupees 68 paise.

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Hint: Use decimal concept.

We know that, 1 rupee = 100 paise. We can reframe these questions as follows:

18 rupees 9 paise from 75 rupees 80 paise

18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,

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49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,

123.68 −49.79−−−−−− 73.89

Which means 73 rupees 89 paise.

Note: We can also perform the subtraction by making all units the same that are paise and then subtract.

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