(x+3)²(65)=x(6)Solve using quadric formula
2 answers:
Answer:
Use the commutative property to reorder the terms ==> 65(x + 3)^2 = x × 6 ==> 6(x + 3)^2 = 6x
Use (a + b)^2 = a^2 + 2ab + b^2 to expand the expression ==> 65(x^2 + 6x + 9) = 6x
Distribute 65 through the parentheses ==> 65^2 + 390x + 585 = 6x
Move the variable to the left-hand side and change its sign ==> 6x^2 + 390x + 585 - 6x = 0
its sign ==> 6x^2 + 390x + 585 - 6x = 0Collect like terms ==> 65x^2 + 384x + 585 = 0
its sign ==> 6x^2 + 390x + 585 - 6x = 0Collect like terms ==> 65x^2 + 384x + 585 = 0Solve the quadratic equation ==> (that part and onward is in the attachment)
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Answer:
115.48
Step-by-step explanation:
This shape can be split into two distinct shapes
Two halves of a semi circle, and a rectangle in between
Circle:
Putting both halves of the semi circle together will give you a full circle. The diameter of the circle is given (7m).
The area of a circle is A = π
The radius, r, is half of the diameter, so 7 / 2 = 3.5m
A = π
A = π *
A = 38.38
Rectangle:
The area of a rectangle is A = h b
The height, h, is known at 7m
The base, b, can be found by removing the length from the dot to the end of the semi circles. This length is the radius of the semi circles, 3.5m
Removing the radius from the total length given
18 - 3.5 - 3.5 = 11m
The base is 11m
A = h b
A = 7 * 11 = 77
Total Area = Circle area + Rectangle area
Total Area = 38.38 + 77 = 115.48