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Sholpan [36]
3 years ago
11

(x+3)²(65)=x(6)Solve using quadric formula​

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
6 0

Step 1: Simplify both sides of the equation.

  • 65x²+390x+585=6x

Step 2: Subtract 6x from both sides.

  • 65x²+390x+585−6x=6x−6x
  • 65x²+384x+585=0

For this equation: a=65, b=384, c=585

  • 65x²+384x+585=0

Step 3: Use quadratic formula with a=65, b=384, c=585

  • x=−b±√b2−4ac/2a
  • x=−(384)±√(384)2−4(65)(585)/
  • 2(65)
  • x=−384±√−4644/130

Therefore, There are no real solutions.

lakkis [162]3 years ago
5 0

Answer:

Use the commutative property to reorder the terms ==> 65(x + 3)^2 = x × 6 ==> 6(x + 3)^2 = 6x

Use (a + b)^2 = a^2 + 2ab + b^2 to expand the expression ==> 65(x^2 + 6x + 9) = 6x

Distribute 65 through the parentheses ==> 65^2 + 390x + 585 = 6x

Move the variable to the left-hand side and change its sign ==> 6x^2 + 390x + 585 - 6x = 0

its sign ==> 6x^2 + 390x + 585 - 6x = 0Collect like terms ==> 65x^2 + 384x + 585 = 0

its sign ==> 6x^2 + 390x + 585 - 6x = 0Collect like terms ==> 65x^2 + 384x + 585 = 0Solve the quadratic equation ==> (that part and onward is in the attachment)

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For Commutative Property of Addition

Let us take a decimal number 2.14 and a fraction \frac{5}{20}

Now, according to the Commutative property of Addition:

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2.14+\frac{5}{20}  = \frac{214}{100}  +\frac{5}{20}

                                   =\frac{214}{100}  + \frac{5 \times 5}{20 \times 5} \\ \\=\frac{214}{100}  + \frac{25}{100} \\ \\= 2.14 + 0.25 \\ \\ = 2.39

Also,

\frac{5}{20} + 2.14  = \frac{5}{20} + \frac{214}{100}

                                     = \frac{5 \times 5}{20 \times 5} +\frac{214}{100} \\ \\= \frac{25}{100}  + \frac{214}{100} \\ \\=  0.25 + 2.14 \\ \\ = 2.39

Therefore, 2.14+\frac{5}{20} = \frac{5}{20} + 2.14

Hence,  Commutative Property of Addition is satisfied.


For Associated Property of Addition

Let us take two same decimal numbers 2.14 , 7.25 and a fraction \frac{5}{20}

Now, according to the Associated property of Addition:

For any three numbers a, b  and  c

a + (b+c) =(a+b) + c

So, for 2.14 , 7.25 and \frac{5}{20}

The Left hand side:

a + (b+c)

2.14 + (7.25 + \frac{5}{20}) = 2.14 + (\frac{725}{100} + \frac{5 \times 5}{20\times 5})

                                                         = 2.14 + (\frac{725}{100} + \frac{25 }{100})

                                                         = 2.14 + (\frac{750}{100} )

                                                        = \frac{214}{100} + \frac{750}{100}

                                                         = \frac{964}{100}

                                                        =9.64


The Right hand side:

(a + b )+c

(2.14 + 7.25 )+ \frac{5}{20}= ( 9.39 ) + \frac{5 }{20}

                                                = 9.39  + \frac{5 \times 5 }{20 \times 5}

                                                = 9.39  + \frac{25}{100}

                                                = 9.39  + 0.25

                                                = 9.64


Thus,

(2.14 + (7.25 + \frac{5}{20} )= (2.14 + 7.25 )+ \frac{5}{20}

Therefore, 2.14+\frac{5}{20} = \frac{5}{20} + 2.14

Hence,  Associative Property of Addition is satisfied.




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