Which operation is NOT closed for polynomials?

Solve for x????????????????????

12345 [234]

$\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }$

$\large\underline{ \boxed{ \sf{✰\: Concept }}}$

➣ Given two paris are linear pairs
➣ We know that sum of linear pairs is equal to 180⁰
➣ Linear :- Having the form of a line; straight or roughly straight; following a direct course.

$\large\underline{ \boxed{ \sf{✛\: Assumptions\:✛ }}}$

➣ let given two angles be p and q that is
➣ angle p is 3x-4
➣ angle q is 3x-8
➣ we have to find "x" in the given expressions

$\large\underline{ \boxed{ \sf{✰\: let's\:solve }}}$

$\rm\angle \: p + \angle \: q = 180 \degree \\$

★ Substituting values

$\rm { \pink➾ \:( 3x - 4) + (3x - 8) = 180} \\ \rm { \pink➾}arranging \: and \: solving \: like \: terms \\ \rm { \pink➾ \: 3x + 3x - 4 - 8 = 180} \\ \rm { \pink➾ \: 6x - 12 = 180} \\ \rm { \pink➾6x = 180 + 12}$

$\qquad \qquad\rm { \pink➾6x = 192} \\ \qquad\qquad\rm { \pink➾ \: x = \frac{ \cancel{192}}{ \cancel6} } \\ \qquad\qquad\rm { \pink➾x = 32}$

★ Hence the value

$\boxed{↪\underline{ \boxed{ \rm{\: x = 32\green✓}}}↩}$

$\rule{70mm}{2.9pt}$

Hope it helps !

5 0

2 years ago

What is x in 4x+4=5x+45

fiasKO [112]

Answer:

Solve for

x

by simplifying both sides of the equation, then isolating the variable.

x = − 41

7 0

4 years ago

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Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 5.08 and angle θA = 25.6 ∘ measured in the sense from the +x

alexgriva [62]

Answer:

(A⃗ ×B⃗ )⋅C⃗ = - 76.415

Step-by-step explanation:

First we need to calculate (A⃗ ×B⃗ ) :

(A⃗ ×B⃗ ) = A.B.sin (α).n

Where A is the magnitude of A⃗

Where B is the magnitude of B⃗

Where α is the angle between A⃗ and B⃗ = 63.9 - 25.6 = 38.3

Finally n is the vector orthogonal to A⃗ and B⃗

n magnitude is 1 and his direction is given by the right hand-rule

so n = ( 0 , 0 , 1 )

(A⃗ ×B⃗ ) = A.B.sin (α).n = 5.08 . 3.94 . sin (38.3) . (0 , 0 , 1 ) = (0,0,12.4)

C⃗ can be written as C.(0,0,-1) because of his +z - direction

C.(0,0,-1) = 6.16.(0,0,-1) = (0,0,-6.16)

(A⃗ ×B⃗ )⋅C⃗ = (0,0,12.4).(0,0,-6.16) = -76.41480787 = -76.415

8 0

3 years ago

Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has

Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0), Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

6 0

3 years ago

If I had $500 dollars sent in the mail and then I spent 400 dollars on groceries how much will I have left.

ollegr [7]

You would have 100 dollars left

6 0

3 years ago

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