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Nata [24]
3 years ago
5

Find QR: 3x+22=10x-41

Mathematics
1 answer:
Tatiana [17]3 years ago
6 0

Answer:

x=9

Step-by-step explanation:

subtract 22 from both sides, simplify 3x = 10x-63, subtract 10x from both sides of the equation, simplify -7x = -63, divide both sides of the equation by the same factor -7x/-7 = -63/-7, then simplify

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What is the slope of the line that passes through the points (3,1) and (-2,5)
evablogger [386]

Answer:

D.) -4/5

Step-by-step explanation:

Ok, so we need to calculate the change in y over the channge in x, rise over run.

(3-(-2)=5     1-5=-4)     -4/5

6 0
3 years ago
Read 2 more answers
If the points A, B and C have the coordinates A(5, 2), B(2, −3) and C(−8, 3), show that the triangle ABC is a right-angled trian
bixtya [17]

Answer:

See below.

Step-by-step explanation:

Triangle ABC will be right-angled if 2 of its sides are perpendicular to each other. When sides are perpendicular the product of their slopes = -1.

Slope  of side AB = (-3-2)/(2-5) = -5/-3 = 5/3

Slope of side BC = (3- -3) / -8-2) = 6/-10 = -3/5

The product of the slopes = 5/3 * -3/5 = -15/15 = -1.

So AB is perpendicular to BC  and triangle ABC is right-angled .

6 0
4 years ago
What is the expected value for the binomial
Pavlova-9 [17]

Answer:

2

Step-by-step explanation:

0(162/3125)+1(162/625)+2(216/625)+3(144/625)+4(48/625)+5(32/3125)

= 2

3 0
3 years ago
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A computer program has a bug that causes it to fail once in every thousand runs, on average. In an effort to find the bug, indep
Serhud [2]

Answer:

The standard deviation of the number of runs required is 2447.26

Step-by-step explanation:

For each run, there are only two possible outcomes. Either the program fails, or it does not. The probability of the computer failing during a run is independent of other runs. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The standard deviation for the expected number of trials for r sucesses is:

\sqrt{V(X)} = \sqrt{\frac{r(1-p)}{p^{2}}}

A computer program has a bug that causes it to fail once in every thousand runs, on average.

This means that p = \frac{1}{1000} = 0.001

In an effort to find the bug, independent runs of the program will be made until the program has failed six times. What is the standard deviation of the number of runs required?

This means that r = 6. So

\sqrt{V(X)} = \sqrt{\frac{6*0.999}{(0.001)^{2}}} = 2447.26

The standard deviation of the number of runs required is 2447.26

8 0
3 years ago
What’s the answer a picture is attached!!! Please answer
SCORPION-xisa [38]
A because if you were doing it on a quadrant or a number line I think that would be the answer! Not 100% sorry
5 0
4 years ago
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