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Assoli18 [71]
3 years ago
5

What is the solution to the open sentence 18 = c + 6?

Mathematics
2 answers:
True [87]3 years ago
8 0
Subtract 6 from both side wich will leaveyou with a answer of 12=c
sveticcg [70]3 years ago
4 0
This is very simple, all you have to do is subtract 18 and 6 and that would be 12, and now we have 12 as a POSSIBLE answer, lets check our work to be 100% correct so now try to add 12 and 6 and we get 18, so yay it made the equation true and since its true its right so that's the answer.

Answer: c = 12 so 18 = 12 + 6 is true.
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<span>Let the original number of seats in a row be x;
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What is the LCM of 18 and 24
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Read 2 more answers
Production of a gas flow meter takes place in two distinct operations. Measurements (n = 15) of the time required for the first
Karolina [17]

Answer:

a) P(a > 80) = 0.323

b) The 95% confidence interval = (73.40, 80.60)

c) The 95% confidence interval expresses that the mean of the distribution can always be found in the given range, with a 95% confidence level.

Step-by-step explanation:

X ~ (45, 4)

Y ~ (32, 2.5)

(X+Y) ~ (77, 6.5)

Let a = (X+Y)

a) Probability that the time required to complete both of those steps will exceed 80 min = P(a > 80)

This is a normal distribution problem

We then standardize 80 min time

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (a - μ)/σ = (80 - 77)/6.5 = 0.46

To determine the probability the time required to complete both of those steps will exceed 80 min = P(a > 80) = P(z > 0.46)

We'll use data from the normal probability table for these probabilities

P(a > 80) = P(z > 0.46) = 1 - P(z ≤ 0.46) = 1 - 0.677 = 0.323

b) 95% confidence interval for the expected total time required to produce one flow meter.

We need to obtain the margin of error

Margin of error = (critical value) × (standard error of the sample)

Critical value for a 95% confidence interval = critical value for a significance level of 5% = t(15-1, 0.05/2) = 2.145 (using the t-score since information on the population mean and standard deviation isn't known)

Standard error for the sample of sum of times = (standard deviation of the sum of times)/√n = (6.5/√15) = 1.678

Margin of error = 2.145 × 1.678 = 3.60

Limits of the confidence interval = (Sample mean ± margin of error)

Lower limit of the confidence interval = (Sample mean - margin of error) = 77 - 3.60 = 73.40

Upper limit of the confidence interval = 77 + 3.60 = 80.60

The confidence interval = (73.40, 80.60)

4 0
3 years ago
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