All categories

3 years ago

When the amplitude of a longitudinal wave

Chemistry

1 answer:

ivanzaharov [21]3 years ago

8 0

Answer:

We learned about this in science

You might be interested in

An equimolar mixture of acetone and ethanol is fed to an evacuated vessel and allowedto come to equilibrium at 65°C and 1.00 atm

frutty [35]

The question is incomplete, the table of the question is given below

Answer:

I) xA= 0.34, yA= 0.55

ii) 76.2 mole % vapor

iii) Percentage of vapor volume = 98%

Explanation:

i) xA= 0.34, yA= 0.55

xA= 0.34, yA= 0.55

ii) 0.50 = 0.55 nv + 0.34 nL

Therefore, nV = 0.762 mol vapor and nL = 0.238 mol liquid

This shows 76.2 mole % vapor

iii) ρA= 0.791 g/cm3 and, ρE = 0.789 g/cm3

Therefore, ρ = 0.790 g/cm3

Now, we have:

MA = 58.08 g/mol and ME= 46.07 g/mol

So Ml = (0.34 x 58.08)+[(1 -0.34) x 46.07] = 50.15 g/mol

1 mol liquid = (0.762 mol vapor/0.238 mol liquid) = 3.2 mol vapor

Liquid volume = Vl= [1 mol x (50.15 g/mol)] / (0.790 g/cm3) = 63.48 cm3

Vapour volume = Vv = 3.2 mol x(22400 cm3/mol) x [(65+273)/273] = 88747 cm3

Therefore, percentage of vapour volume = 88747 / (88747+63.48) = 99.9 %

3 0

3 years ago

The average human body temperature is 98.6 °

grin007 [14]

It's 37 degrees Celsius

3 0

3 years ago

sp2 hybrid orbitals have 1. trigonal bipyramidal symmetry. 2. linear symmetry. 3. tetrahedral symmetry. 4. trigonal planar symme

Cloud [144]

Answer:

4. trigonal planar symmetry.

Explanation:

The sp2 hybridization is formed with one s and two p atomic orbitals and form trigonal planar symmetry. In sp2 hybridization, there are same valence shell in both the orbitals and it gives three equivalent sp2 hybridized orbitals that are separated by 120 degrees giving trigonal planar symmetry.

Hence, the correct answer is "4. trigonal planar symmetry.".

7 0

3 years ago

Lucia wants to develop a process for dyeing shirts so that the color will not fade when the shirt is washed. She proceeds with t

Firlakuza [10]

I cant because it not full

3 0

4 years ago

Read 2 more answers

Balance the following oxidation-reduction reactions, which take place in acidic solution, by using the "half-reaction" method.

LuckyWell [14K]

First identify which is being oxidized and reduced. In this case, the Mg is being oxidized and the Hg is being reduced.

Mg --> Mg+2

<span>Hg+2 --> Hg+1
</span>
Then you have to balance each half reaction first with electrons before adding them together in one equation

$Mg$ ⇒ $Mg^{+2} + 2e^{-1}$

and

$2Hg^{+2} + 2e^{-1}$ ⇒ $Hg_{2} ^{+2}$

and then combine them together to form

$Mg + 2 Hg^{+2} + 2e$ ⇒ $Mg^{+2} + 2e ^{-} + 2 Hg^{+1} + 2 e^{-}$

It isn't necessary to keep the electrons but its essential to know how many there are in order to know how many are in the equation in order to calculate the reaction energy. Note: A<span>dd H+ and H2O to balance the H's and O's in acidic solution if needed.</span>

8 0

4 years ago