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Scrat [10]
3 years ago
6

Functions A and B give the population of City A and B respectively, t years since 1990. In each function, population is measured

in millions.
Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0

Answer:

B(4) > A(4)

t = 6

Step-by-step explanation:

Given

City\ A \to Purple

City\ B \to Blue

See attachment for both functions

Solving (a): Which is greater in A(4) and B(4).

From the readings of the graph

A(4)= 1.8

B(4) = 2.6

By comparison:

B(4) > A(4) because 2.6 > 1.8

Solving (b): When is A(t) = B(t)

From the readings of the graph

A(t) = B(t) when t = 6

i.e.

A(t) = B(t) = 3\ million

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The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
Help me please. if you need anymore information then ask.
oee [108]
45
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You have to add 25 for each one so you get the answer
6 0
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I need help. Please show work
telo118 [61]
◆ Area related to Circles ◆

Hey !!

Check the attachment.
Hope it helps you :)

7 0
3 years ago
What is the answer 9c-5=13?
riadik2000 [5.3K]
C is 2 because you have to move the 5 so you add 5 to 13 which is 18 then divide both sides by 9 so it's 2
3 0
3 years ago
I need question 3 only
dsp73

Answer:

  • table: 14, 16, 18
  • equation: P = 2n +12

Step-by-step explanation:

Perimeter values will be ...

rectangles . . . perimeter

  1 . . . 14

  2 . . . 16

  3 . . . 18

__

The perimeter of a figure is twice the sum of the length and width. Here, the length is a constant 6. The width is n, the number of rectangles. So, the perimeter is ...

  P = 2(6 +n) = 12 +2n

Your equation is ...

  P = 2n +12 . . . . . . . . perimeter P of figure with n rectangles.

_____

<em>Additional comment</em>

You may be expected to write the equation using y and x for the perimeter and the number of rectangles. That would be ...

  y = 2x +12 . . . . . . . . . perimeter y of figure with x rectangles

4 0
3 years ago
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