3 years ago

Given: ABCD is a rhombus. Prove: △AEB is a right triangle.

Mathematics

1 answer:

lukranit [14]3 years ago

4 0

Answer:

Step-by-step explanation:

∵ ABCD is a rhombus

∴ AC is ⊥ on BD

∴ ΔAEB is right angled triangle

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Find two different planes whose intersection is theline:x = 6 + 3ty = -8 - 3tz = -1 - tWrite equations for each plane in the for

alina1380 [7]

Answer:

$x+y=-2$ and $3z-y=5$ are two such planes.

Step-by-step explanation:

To find the two planes whose intersection is the line

$x=6+3t\\ y=-8-3t\\ z=-1-t$

You can say that t is equal to this expression

$t=\frac{x-6}{3} =\frac{y+8}{-3}=-z-1$

Next,

$\frac{x-6}{3} =\frac{y+8}{-3}\\ \frac{y+8}{-3}=-z-1$

Then,

$x+y=-2$ and $3z-y=5$ are two such planes.

You can see in the image attached that the intersection of this planes is the line

$x=6+3t\\ y=-8-3t\\ z=-1-t$

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Answer:

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Step-by-step explanation:

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Tha answer is F

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3 years ago

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laila [671]

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The pirce of an item yesterday was$125 . Today, the price fell to 75. Find the percentage decrease.

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GL Deary

Hope I helped!!!

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