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Zielflug [23.3K]
3 years ago
7

Amanda has a job that pays $92,000 per year. How much will she pay in social security taxes? (Social security taxes are 6.2% of

earnings
Mathematics
2 answers:
kykrilka [37]3 years ago
8 0
She will have to pay $5,704 in social security taxes. 
-In order to find 6.2% of 92,000 you have to multiply .062 * 92,000. This will get you $5,704. 
Ierofanga [76]3 years ago
8 0
She will pay 5,704$ (My calculations: 92,000x0.062(6.2%)= 5,704$
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Answer:

9

Step-by-step explanation:

the biggest number gets eaten by the alligator

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3 years ago
A cosine function has a period of 4, a maximum value of 20, and a minimum value of 0. The function is not a reflection of its pa
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the third one

Step-by-step explanation:

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3 years ago
Jerome found the lengths of each side of triangle QRS as shown, but did not simplify his answers. Simplify the lengths of each s
tankabanditka [31]

Answer:

D. Triangle QRS is an isosceles triangle because QR = RS.

Step-by-step explanation:

Find the length of each side of the triangle using the formula for calculating the distance between two points.

D = √(x2-x1)²+(y2-y1)²

For side RS

R(0,0) and S(5, -3.322)

RS = √(5-0)²+(-3.322-0)²

RS = √25+11.035684

RS = √36.035684

RS = 6.0029

For side RQ

R(0,0) and Q(-3, -5.2)

RQ = √(-3-0)²+(-5.2-0)²

RQ = √9+27.04

RQ = √36.04

RQ = 6.0033

For side QS

Q(-3,-5.2) and S(5, -3.322)

QS = √(5+3)²+(-3.322+5.2)²

QS = √64+3.526884

QS = √67.526884

QS = 8.22

From the calculation it can be seen that RS=QR

Since the two sides f the triangle are equal, hence the triangle is an isosceles triangle. An isosceles triangle is a triangle that has two of its sides equal

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3 years ago
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7 0
2 years ago
Read 2 more answers
Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

and

sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

Find cos(X)

we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

7 0
3 years ago
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