A) 0.11 W B) 1.1 W C) 2.3 W D) 4.5 W
2 answers:
You might be interested in
Answer:
Explanation:
Given:
height above which the rock is thrown up,
initial velocity of projection,
let the gravity on the other planet be g'
The time taken by the rock to reach the top height on the exoplanet:
where:
final velocity at the top height = 0
(-ve sign to indicate that acceleration acts opposite to the velocity)
The time taken by the rock to reach the top height on the earth:
Height reached by the rock above the point of throwing on the exoplanet:
where:
final velocity at the top height = 0
Height reached by the rock above the point of throwing on the earth:
The time taken by the rock to fall from the highest point to the ground on the exoplanet:
(during falling it falls below the cliff)
here:
initial velocity= 0
Similarly on earth:
Now the required time difference:
Answer:
The distance is
Explanation:
From the question we are told that
The focal length is
Generally the lens equation is mathematically represented as
At image distance u = 1.5 m
=>
=>
At image distance
=>
=>
The distance the lens need to move is evaluate as