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Luda [366]
3 years ago
13

Can someone help me with this real quick?

Physics
1 answer:
ch4aika [34]3 years ago
4 0

Answer:

7,546 J

Explanation:

recall that Potential energy is given by

P.E = mgΔh

where m = 70kg (given)

g = 9.8 m/s² (acceleration due to gravity)

Δh = change in height

= distance from top of building to top of car

= height of building - height of car

= (5+8) - 2

= 11m

substituting all these into the equation:

P.E = mgΔh

= 70 x 9.8 x 11

= 7,546 J

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I would help them out and try to comfort and protect them from what was making them feel like that
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4 years ago
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The change in the internal energy of a system that releases 2,500 j of heat and that does 7,655 j of work on the surroundings is
g100num [7]

We are given that the system “releases” heat of 2,500 J, and that it “does work on the surroundings” by 7,655 J.

The highlighted words releases and does work on the surroundings all refers to that it is the system itself which expends energy to do those things. Therefore the action of releasing heat and doing work has both magnitudes of negative value. Therefore:

heat released = - 2, 500 J

work done = - 7, 655 J

Which means that the total internal energy change of the system is:

change in internal energy = heat released + work

<span>change in internal energy = - 2, 500 J +  - 7, 655 J</span>

<span>change in internal energy = -10,155 J</span>

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4 years ago
A 5 kg pineapple is hanging completely still in mid air on a string and suddenly explodes
11111nata11111 [884]

Answer:

Explanation:

Conservation of momentum

Initial momentum is zero

3(15) + 2(v) = 0

v = - 22.5 m/s

v = 22.5 m/s downward

3 0
3 years ago
Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu
Oxana [17]

The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

F- mg sin \theta - \mu_k R = ma (1)

where :

F = 10,000 N is the force applied by Noah

mg sin \theta is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=10^{\circ}  is the angle of incline

\mu_k R is the force of friction, where:

\mu_k is the coefficient of friction

R is the normal reaction  

and a is the acceleration

Perpendicular direction:

R-mg cos \theta =0 (2)

where mg cos \theta is the component of the weight perpendicular to the incline

From (2) we find

R=mg cos \theta

And substituting into (1)

F-mg sin \theta - \mu_k mg cos \theta = ma

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

F-mg sin \theta - \mu_k mg cos \theta=0

And we can re-arrange it to find the coefficient of friction:

F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

4 0
3 years ago
When running on its 11.4 V battery, a laptop computer uses 8.3 W. The computer can run on battery power for 8.5 h before the bat
AveGali [126]

Answer:

The laptop battery is capable of supplying 253980 J.

Explanation:

Given;

voltage of the battery, V = 11.4 V

power consumed by the laptop, P = 8.3 W

duration of the battery before depletion, t = 8.5 hours

Determine the amount of energy supplied by the laptop battery within 8.5 hours.

Energy, E = Power x time

Energy, E = 8.3 W x 8.5 h = 70.55 Wh

Energy, E in joules = 70.55 wh x 3600 s/h = 253980 J

Therefore, the amount of energy supplied by the laptop battery within 8.5 hours is 253980 J.

7 0
3 years ago
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