7.89•10 to the third power
The car travels a distance <em>d</em> from rest with acceleration <em>a</em> after time <em>t</em> of
<em>d</em> = 1/2 <em>a</em> <em>t</em>²
It covers 69 m with 2.8 m/s² acceleration, so that
69 m = 1/2 (2.8 m/s²) <em>t</em>²
<em>t</em>² = 2 (69 m) / (2.8 m/s²)
<em>t</em> ≈ 7.02 s
where we take the positive square root because we're talking about time *after* the car begins accelerating.
Answer:
it's right you did a great job
it's 1727 +822 just kidding
The balanced combustion reaction
for butane is;
2C4H10 + 13O2 → 8CO2 + 10H2O
Molar mass of water = 18.02
g/mol
Molar mass of oxygen = 32 g/mol
2.46g H2O(1 mol H2O/18.02g)(13
mol O2/10 mol H2O)(32g O2/1 mol O2) = 5.68g O2