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riadik2000 [5.3K]
3 years ago
6

It is always a good idea to get some sense of the "size" of units. For example, the mass of an apple is about 100 g , whereas a

bicycle is about a hundred times more massive at around 10 kg . Estimate the mass of the objects.

Physics
1 answer:
marta [7]3 years ago
4 0

Answer and Explanation:

The estimation of the mass of the objects is as follows

Given that

The mass of an apple is about 100 g

Just like that, we do some estimation of different objects

A dime is around 1 g

A smartphone is about 100 g

An adult male is approx 100 kg

A college physics textbook is around 1 kg

A ripe banana is around 100 g

A small car is around 1,000 kg

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bezimeni [28]

Answer:

True

Explanation:

I play

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3 years ago
Use the component form of newton's second law to write an expression for the x component of the net force, σfx
nordsb [41]

Draw a free body diagram to show which forces act in the x and y directions. The x component equation is σfx = 0. The σfx being all the forces acting in the x direction.
8 0
3 years ago
A toaster using a Nichrome heating element operates on 120 V. When it is switched on at 28 ∘С, the heating element carries an in
sukhopar [10]

Answer:

The final temperature of the element = 262.67°C

The power dissipated in the heating element initially = 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A = 147.60 W

Explanation:

Our given parameters include;

A Nichrome heating element operates on 120 V.

Voltage (V) = 120V

Initial Current (I₁) = 1.36 A

Initial Temperature (T₁) = 28°C

Final Current (I₂) = 1.23 A

Final Temperature (T₂) = unknown ????

Temperature dependencies of resistance is given by:

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]            ----------------------    (1)

in which R₁ is the resistance at temperature T₁

R_{T(2) is the resistance at temperature T₂

Given that V= IR

R = \frac{V}{I}

Therefore, the resistance at temperature 28°C is;

R_{28}= \frac{120V}{1.36A}

= 88.24Ω

R_{T(2) = \frac{120V}{1.23A}

= 97.56Ω

From (1) above;

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]      

97.56 = 88.24 [ 1 + 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)]

\frac{97.56}{88.24}= 1+(4.5*10^{-4})(T-28^0C)

1.1056 - 1 = 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)

0.1056 = 4.5×10⁻⁴(T₂-28°C)

\frac{0.1056}{4.5*10^{-4}}= T-28^0C

T - 28° C = 234.67

T = 234.67 + 28° C

T = 262.67 ° C

(b)

What is the power dissipated in the heating element initially and when the current reaches 1.23 A

The power dissipated in the heating element initially can be calculated as:

P = I²₁R₂₈

P = (1.36A)²(88.24Ω)

P = 163.209 W

P ≅ 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A can be calculated as:

P= I^2_2R_{T^0C

P = (1.23)²(97.56Ω)

P = 147.598524

P ≅ 147.60 W

6 0
3 years ago
The least common fossils are those that have been<br> petrified<br> frozen<br> buried<br> distilled
Alchen [17]

Answer: Frozen fossils

6 0
3 years ago
The noise level coming from a pig pen with
sweet [91]

Answer:

The decibel of the remaining pigs is 51.5 dB.

Explanation:

Decibel (dB) is a unit of measure of the intensity of a given sound.

Number of pigs = 199, noise level = 74.3 dB.

Given that the intensity (I) of the sound from the pen is proportional to the number of pigs (N), thus:

                       I    \alpha  N

                       I = kN

where k is the constant of proportionality.

⇒                    k = \frac{I}{N}

                         = \frac{74.3}{199}

                      k = 0.3734

When 61 numbers of pigs were removed, the number of remaining pigs (N) squealing at their original level is 138.

Thus, the becibel level (I) of the remaining pigs can be determined by:

                  I = kN

                    = 0.3734 × 138

                   = 51.53 dB

The becibel level (I) of the remaining pigs is 51.53 dB.

6 0
3 years ago
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