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3 years ago

Does a light bulb at a temperature of 2500K produce as white a light as the sun at 6000K

Physics

1 answer:

sattari [20]3 years ago

7 0

Answer:

No. ... UV light causes sunburn, whereas visible light does not.

Explanation:

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What represents the third dimension in a topographic map and shows elevation?

IgorC [24]

An object or any location can be represented on a two-dimensional surface like a paper or computer screen. This representation is known as map. Most maps do not take into account the elevation of the object or the location they representing. On the other hand, Topographic maps use contour lines to represent the third dimension and to show elevation change on or below the surface of the earth.

3 0

3 years ago

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Which form of the law of conservation of energy describes the motion of the block when it slides from the top of the table to th

Mnenie [13.5K]

By definition we have that the energy at the top of the ramp is equal to the energy at the bottom of the ramp. This is due to the principle of energy conservation.

We have then:

$E1 = E2$

The energy at the top is only potential energy:

$E1 = mgh$

Where,

m: mass
g: acceleration of gravity
h: vertical height of the ramp

The energy when it falls is transformed into kinetic energy and therefore:

$E2 = \frac {1} {2} mv ^ 2$

Where,

v: object speed.

Therefore we have:

$mgh = \frac {1} {2} mv ^ 2$

Answer:

The potential energy is transformed into kinetic energy.

$mgh = \frac {1} {2} mv ^ 2$

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3 years ago

What is the acceleration at 3 seconds? Please explain your answer. Thank you :]

statuscvo [17]

Answer:

$-3 m/s^{2}$

Explanation:

Acceleration on a VT graph is the slope of the line at the given point. We can find the slope at 3 with Δy/Δx. This gives us (4-2)/(3-(-3)) which works out to be -3m/s^2

8 0

3 years ago

The terminals of a 0.70 Vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm What is the current

Komok [63]

Answer:

$I=0.047A$

Explanation:

Let's use Ohm's law:

$V=IR$

$I=\frac{V}{R}$ (1)

Where:

$V=Voltage\\I=Current\\R=Electrical\hspace{2 mm}Resistance$

We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:

$R=\rho*\frac{l}{A}$ (2)

Where:

$R=Electrical\hspace{2 mm}Resistance\\l=Length\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=80m\\A=Cross\hspace{2 mm}sectional\hspace{2 mm}area\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=1.256637061*10^{-7} \\\rho=Electrical\hspace{2 mm}resistivity\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}material=2.35*10^{-8}$

Keep in mind that the electrical resistivity of the gold is a known constant which is $\rho_g_o_l_d=2.35*10^{-8}$ and the cross sectional area of the conductor is calculated as: