All categories

2 years ago

What is the length of QR

Mathematics

2 answers:

raketka [301]2 years ago

8 0

Answer:

Step-by-step explanation:

Set 3n-1=5n-7.

Solve.

n=3.

Plug in 3 to 5n-7.

QR=8

Rus_ich [418]2 years ago

8 0

Answer:

QR=8

Step-by-step explanation:

so using the fact that the two triangles are congruent, we can determine:

5n-7=3n-1

5n-6=3n

2n-6=0

n=3

so we replace all n in 5n-7 with three

5x3-7

15-7

You might be interested in

Simplify. Assume that no denominator is equal to zero. ([3^2]^3g^3h^4)^2

mariarad [96]

Answer:

531,441·g^6·h^8

Step-by-step explanation:

The operative rule of exponents is ...

(a^b)^c = a^(b·c)

Working from the inside out, according to the order of operations, we get ...

= (9^3·g^3·h^4)^2

= 729^2·g^(3·2)·h^(4·2)

= 531,441·g^6·h^8

7 0

3 years ago

K=mv^2/2<br> Find derivative of k

jonny [76]

Answer: I think. it's 0

Step-by-step explanation:

5 0

3 years ago

Robert is building model cars as well as model trains. The cars take 4 hours to build while the trains take 6 hours

Darina [25.2K]

10 cars and 10 trains in 100 hours

it approximately take him 10 hours to build one car and one train how 6+4=10 how many times can 10 go into 100 10 times hope this helps a little

4 0

3 years ago

In the early months of some year, one site added 0.2 million new accounts every day. at this rate, how many days would be need

inessss [21]

50 days needed for 10 million new account
5 days for 1 million
1 day for 0.2 million

3 0

3 years ago

Read 2 more answers

manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin

alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) $nCr q^{r} p^{n-r}$

$nCr = \frac{n!}{(n-r)!r!}$

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = $20C18 * 0.97^{18} * 0.03^{20-18}$

P(X=18) = $20C18 * 0.97^{18} * 0.03^{2}$

P(X=18) = 0.0988

P(X=19) = $20C19 * 0.97^{19} * 0.03^{20-19}$

P(X=19) = $20C19 * 0.97^{19} * 0.03^{1}$

P(X=19) = 0.3364

P(X=20) = $20C20 * 0.97^{20} * 0.03^{20-20}$

P(X=20) = $20C20 * 0.97^{20} * 0.03^{0}$

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0

3 years ago