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FinnZ [79.3K]
3 years ago
6

One section of the reporting period test in history had 35 true or false questions. Maria answered 75% of the questions correctl

y. How many of the questions did she answer incorrectly?
Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0

Answer:

29 correct

Step-by-step explanation:

i honestly dont know how to explain this so its probably wrong but you know...

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Interior and Exterior Triangle Angles
Luden [163]

Sum of two interiors=exterior

\\ \rm\bull\rightarrowtail 2x-3+2x+15=7x-18

\\ \rm\bull\rightarrowtail 4x+12=7x-18

\\ \rm\bull\rightarrowtail 3x=30

\\ \rm\bull\rightarrowtail x=10

  • m<GHI=2(10)-3=17
6 0
2 years ago
In Spring 2017, data was collected from a random selection of STA 2023 students. One of the questions asked how many hours they
Arte-miy333 [17]

Answer: 0.22

Step-by-step explanation:

We know that the best point estimate for the difference between two population mean is the difference between their sample means.

Given : For the 39 randomly selected upperclassmen, the sample mean was 0.12 and sample standard deviation was 0.42. For the 35 randomly selected underclassmen, the sample mean was 0.34 and the sample standard deviation was 0.87.

Let A denotes the population of upperclassmen and B denotes the population of underclassmen .

\overline{x}_A=0.12

\overline{x}_B=0.34

Then, the point estimate of the difference in the population mean volunteered between underclassmen and upperclassmen will be :-

\overline{x}_B-\overline{x}_A=0.34-0.12=0.22

Hence, the point estimate of the difference in the population mean volunteered between underclassmen and upperclassmen =0.22

5 0
3 years ago
A student conducts several random surveys to find out the most preferred lunch option. Each survey was of 60 students. No studen
stira [4]

Answer:

A

C

is the answer

I think soo

5 0
2 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
Select ALL the correct answers.
IgorC [24]

Answer:

A. 4(x - 4) + 2(3x² + 3x - 20)

C. (11x² + 7x - 55)-(5x² - 3x + 1)

F. (3x² + 5x - 28) + (3x² + 5x - 28)

Step-by-step explanation:

Given:

(3x-7)(2x+8)

= 6x² + 24x - 14x - 56

=6x² + 10x - 56

A. 4(x - 4) + 2(3x² + 3x - 20)

= 4x - 16 + 6x² + 6x - 40

= 6x² + 10x - 56

B. (3x² + 5x - 28) - (2x² + 4x + 28)

= 3x² + 5x - 28 - 2x² - 4x - 28

= x² + x - 56

C. (11x² + 7x - 55)-(5x² - 3x + 1)

= 11x² + 7x - 55 - 5x² + 3x - 1

= 6x² + 10x - 56

D. 4(x - 4) - 2(3x² + 3x - 20)

= 4x - 16 - 6x² - 6x + 40

= - 6x² - 2x + 24

E. (11x² + 7x - 55)-(5x² - 3x + 2)

= 11x² + 7x - 55 - 5x² + 3x - 2

= 11x² - 5x² + 7x + 3x - 55 - 2

= 6x² + 10x - 57

F. (3x² + 5x - 28) + (3x² + 5x - 28)

= 3x² + 5x - 28 + 3x² + 5x - 28

= 6x² + 10x - 56

7 0
2 years ago
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