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djyliett [7]
3 years ago
6

What percent of 40 is 5​

Mathematics
1 answer:
horsena [70]3 years ago
6 0

Answer:

12.5%

Step-by-step explanation:

Five divided by 40 is 12.5

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Simplify the following polynomial and write the answer in standard form. (-2x^3+5x^2-4x+8)-(-2x^3+2x-3)
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(-2x^3+5x^2-4x+8)-(-2x^3+2x-3)\\\\=-2x^3+5x^2-4x+8-(-2x^3)-2x-(-3)\\\\=-2x^3+5x^2-4x+8+2x^3-2x+3\\\\=(-2x^3+2x^3)+5x^2+(-4x-2x)+(8+3)\\\\=5x^2-6x+11
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Todd is training to bike in the Turkey Trot Bike Race and rode his bike 7 ¾ miles per hour for 2 2/3 hours. How many miles did T
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5 0
3 years ago
In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.
vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

<u>Solution:</u>

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>

\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100

\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}

<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

7 0
3 years ago
Please help me find the area for this hexagon (please show work to) ,:)
kvasek [131]

Check the picture below.

so the area of the hexagon is really just the area of two isosceles trapezoids.

\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}

4 0
2 years ago
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