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Shalnov [3]
3 years ago
11

Help pls hw 14 and 15 mostly those the rest I’ll do

Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0
<h3>Answer:</h3><h3>14)38.1</h3><h3>15)56.58</h3><h3>16)9.38</h3><h3>17)9</h3><h3>18)6.4</h3><h3>Step-by-step explanation: Addition and Subtraction</h3>

Olenka [21]3 years ago
3 0

Answer:

Answer 14

Step-by-step explanation:

answer 37.38

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Reduce to the lowest term: 30/40
natulia [17]

Answer:

3/4

Step-by-step explanation:

Reduce both the numerator and the denominator by 10, their greatest common factor.

6 0
3 years ago
For a school fundraiser mai will make school spirit bracelets. She will order bead wiring and alphabet beads to create the schoo
Andreas93 [3]

Answer:

235 bracelets

Step-by-step explanation:

Mai must spend $250 on wire and $5.30 per bracelet beads. Mai creates the expression.

We are given the equation:

5.3n+ 250 to represent the cost of making n bracelets.

The maximum number of bracelets Mai can make with a budget of $1500 Is calculated as:

$1500 = 5.3n+ 250

Collect like terms

1500 - 250 = 5.3n

1250 = 5.3n

n = 1250/5.3

n = 235.8490566 bracelets.

Bracelets are created as whole numbers and they can't be in decimal form.

Therefore, the maximum number of bracelets Mai can make with a budget of $1500 is 235 bracelets.

6 0
3 years ago
4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (
Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0
3 years ago
What would be the steps to solving this problem?<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D" id="TexFormula
lidiya [134]
Isolate the variable by dividing each side by factors that don’t contain the variable.

X = -2

Hope this helps!
Have a great day!
3 0
2 years ago
Read 2 more answers
Is 8 x 6 =(4×6)+(4×6)true or false
creativ13 [48]
Yes 8*6=48 and 4*6+4*6=48
4 0
3 years ago
Read 2 more answers
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