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3 years ago

When do we use statistics in real life?

1 answer:

5 0

We can use statistics in pretty much anything, for example if someone is studying the rate of car accidents involving teen drivers, they would use statistics.

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Part A: Explain why x = 5 makes 4x - 1 3 19 true but not 4x - 1 19

Olenka [21]

Answer:

Part A: Explain why x = 5 makes 4x - 1 ≤ 19 true but not 4x - 1 < 19

Part B: x=9

Step-by-step explanation:

Part A: Because the first one is less than or equal to 19 and the other is just less than.

x = 5

TRUE: 4x - 1 ≤ 19 = 20-1 ≤ 19 = 19 ≤ 19

19 is less than or equal to 19 so its true

FALSE: 4x - 1 < 19 = 19 < 19

19 is not greater than 19

Part B:

5x + 2 = 47 subtract 2 from both sides

5x = 45 divide both sides by 5

x = 9

To check we can plug it back in

5x + 2 = 47

5(9) + 2 = 47

45 + 2 = 47

47 = 47

TRUE

5 0

3 years ago

How do you do two x to the second plus nine x minus five equal zero

Amanda [17]

Answer: are you asking what is the answer?

Step-by-step explanation:

8 0

3 years ago

There is a bag with only milk and dark chocolates.

Novay_Z [31]

Answer:

12 milk chocolates.

Step-by-step explanation:

-We know that probabilities add upto 1:

$P(milk)+P(dark)=1\\\\P(milk)+\frac{7}{9}=1\\\\P(milk)=\frac{2}{9}$

Let X be the total number of chocolates. We know that probability is the successful events divided by the total number of events:

$P(dark)=\frac{dark \ events}{total \ events}\\\\\\\frac{7}{9}=\frac{42}{X}\\\\X=54$

#We subtract the number of dark chocolates from X to get the number of milk chocolates:

$N_m=X-N_d\\\\=54-42\\\\=12$

Hence, there must be 12 milk chocolates.

6 0

3 years ago

A pole that is 2.6 m tall casts a shadow that is 1.03 m long. At the same time, a nearby tower casts a shadow that is 46.25 m lo

photoshop1234 [79]

Answer:

Therefore the height of the tower is 116.75 m.

Step-by-step explanation:

Given that a pole that is 2.6 m tall casts a shadow that is 1.03 m long.

Here the height of a object directly proportional to the shadow. It means

Height of the object ∝ shadow

Height of the object= k.shadow

[k is the proportional constant.]

$\Rightarrow \frac{h}{s} =k$ [Height of object is denoted by h and shadow is denoted by s]

Then,

$\frac{h_1}{s_1} =k$ [h₁ is the height of the pole and s₁is the length of the shadow]

Again for the tower

$\frac{h_2}{s_2}=k$ [h₂ is the height of the tower and s₂ is the length of the shadow]

Therefore,

$\frac{h_1}{s_1}=\frac{h_2}{s_2} =k$

$\Rightarrow\frac{h_1}{s_1}=\frac{h_2}{s_2}$ ............(1)

Given $h_1 = 2.6 m$ , $s_1=1.03m$ and $s_2=46.25m$

Putting the value of $h_1,s_1$ and $s_2$ equation (1)

$\frac{2.6}{1.03}=\frac{h_2}{46.25}$

$\Rightarrow h_2 \times1.03= 2.6\times 46.25$ [cross multiplication]

$\Rightarrow h_2 = \frac{2.6\times 46.25}{1.03}$

$\Rightarrow h_2= 116.75$

Therefore the height of the tower is 116.75 m.

3 0

3 years ago

Write the decimal equivalent for each fraction. − 1 2 1 3 − 1 4 1 5 1 6 − 1 8 1 10

s344n2d4d5 [400]

If you sort out the fractions better I can for sure help:)) I just need to know every fraction it’s hard to tell by what you wrote:))

4 0

4 years ago