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Oxana [17]
3 years ago
5

When do we use statistics in real life?

Mathematics
1 answer:
bazaltina [42]3 years ago
5 0
We can use statistics in pretty much anything, for example if someone is studying the rate of car accidents involving teen drivers, they would use statistics.
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Part A: Explain why x = 5 makes 4x - 1 3 19 true but not 4x - 1 19
Olenka [21]

Answer:

<em>Part A</em>: Explain why x = 5 makes 4x - 1 ≤ 19 true but not 4x - 1 < 19

<em>Part B: x=9</em>

Step-by-step explanation:

<u>Part A</u>: Because the first one is less than or equal to 19 and the other is just      less than.

x = 5

TRUE:   4x - 1 ≤ 19    =    20-1 ≤ 19    =    19 ≤ 19  

             19 is less than or equal to 19 so its true

FALSE:  4x - 1 < 19    =    19 < 19  

              19 is not greater than 19

<u>Part B:</u>  

5x + 2 = 47  subtract 2 from both sides

5x = 45  divide both sides by 5

x = 9

To check we can plug it back in

5x + 2 = 47

5(9) + 2 = 47

45 + 2 = 47

47 = 47

TRUE

5 0
3 years ago
How do you do two x to the second plus nine x minus five equal zero
Amanda [17]

Answer: are you asking what is the answer?

Step-by-step explanation:

8 0
3 years ago
There is a bag with only milk and dark chocolates.
Novay_Z [31]

Answer:

12 milk chocolates.

Step-by-step explanation:

-We know that probabilities add upto 1:

P(milk)+P(dark)=1\\\\P(milk)+\frac{7}{9}=1\\\\P(milk)=\frac{2}{9}

Let X be the total number of chocolates. We know that probability is the successful events divided by the total number of events:

P(dark)=\frac{dark \ events}{total \ events}\\\\\\\frac{7}{9}=\frac{42}{X}\\\\X=54

#We subtract the number of dark chocolates from X to get the number of milk chocolates:

N_m=X-N_d\\\\=54-42\\\\=12

Hence, there must be 12 milk chocolates.

6 0
3 years ago
A pole that is 2.6 m tall casts a shadow that is 1.03 m long. At the same time, a nearby tower casts a shadow that is 46.25 m lo
photoshop1234 [79]

Answer:

Therefore the height of the tower is 116.75 m.

Step-by-step explanation:

Given that a pole that is 2.6 m tall casts a shadow that is 1.03 m long.

Here the height of a object directly proportional to the shadow. It means

Height of the object ∝ shadow

Height of the object= k.shadow

[k is the proportional constant.]

\Rightarrow \frac{h}{s} =k    [Height of object is denoted by h and shadow is denoted by s]

Then,

\frac{h_1}{s_1} =k       [h₁ is the height of the pole and s₁is the length of the shadow]

Again for the tower

\frac{h_2}{s_2}=k      [h₂ is the height of the tower and s₂ is the length of the shadow]

Therefore,

\frac{h_1}{s_1}=\frac{h_2}{s_2} =k

\Rightarrow\frac{h_1}{s_1}=\frac{h_2}{s_2}............(1)

Given h_1 = 2.6 m  ,s_1=1.03m  and   s_2=46.25m

Putting the value of h_1,s_1 and s_2  equation (1)

\frac{2.6}{1.03}=\frac{h_2}{46.25}

\Rightarrow h_2 \times1.03= 2.6\times 46.25          [cross multiplication]

\Rightarrow h_2 = \frac{2.6\times 46.25}{1.03}

\Rightarrow h_2= 116.75

Therefore the height of the tower is 116.75 m.

3 0
3 years ago
Write the decimal equivalent for each fraction.<br> − 1 2 1 3 − 1 4 1 5 1 6 − 1 8 1 10
s344n2d4d5 [400]
If you sort out the fractions better I can for sure help:)) I just need to know every fraction it’s hard to tell by what you wrote:))
4 0
4 years ago
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