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iren [92.7K]
4 years ago
10

Which statement about rational numbers is not correct?

Mathematics
1 answer:
Elodia [21]4 years ago
4 0
D. All Rational Numbers Can Be Written In The Form A/B

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3 coins Priya spends $45 on gas, $10 on dinner, and $8 on a video game. How much money did Priya spend on variable expenses?​
NISA [10]

Answer:

3x=63

Step-by-step explanation:

3 coins means a coin is x and total expenditure is equal to 63

8 0
3 years ago
Help,anyone can help me do quetion,I will mark brainlest.​
Serhud [2]

Answer:

a)    x = 2

b)    x = 4

Step-by-step explanation:

a = (b₁ + b₂)/2 * h

----------------------------

a)

48 = (10 + x)/2 * 8

Divide both sides by 8

6 = (10 + x)/2

multiply both sides by 2

12 = 10 + x

Subtract 10 from both sides

2 = x

x = 2

---------------------------------

b)

18 = (7 + 2)/2 * x

18 = 4.5 * x

divide both sides by 4.5

4 = x

x = 4

5 0
3 years ago
Read 2 more answers
Please help ASAP!!!!<br><br> Which type of transformation is shown ?
NikAS [45]

Answer:

you have to do it yourself

4 0
3 years ago
Solve liner equation for they variable<br> 3x-5(x+6)=-2x-2(5+10)
Dvinal [7]

Answer:

all numbers

Step-by-step explanation:

3x - 5(x + 6) = -2x -2(5 + 10)

Distribute on both sides.

3x - 5x - 30 = -2x - 10 - 20

Add 2x to both sides.

-2x - 30 = -2x - 30

-30 = -30

Since we get a true statement after only doing legal steps to solve the equation, the equation has an infinite number of solutions.

Answer: all numbers

4 0
3 years ago
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
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