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Mashcka [7]
2 years ago
5

How do I do this I need help I don’t wanna fail this quarter!!!!

Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
8 0

Answer:

SSA

Step-by-step explanation:

Side Side Angle

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A jetski rental company charges a $50 deposit, plus $25 per hour to rent a jetski. This can be represented by the formula T = 25
loris [4]

Answer:

None, the answer will be the same

Step-by-step explanation:


4 0
3 years ago
The speed limit is 25 miles per hour, but it seems that many of the cars are going faster. The city places 2 counter strips 360
klio [65]
You figure out how long it would take a car traveling at 25 mph
to cover 360 ft.  Any driver who does it in less time is speeding.

           (25 mi/hr) · (5,280 ft/mile) · (1 hr / 3,600 sec)

       =    (25 · 5280 / 3600)  ft/sec  =  (36 and 2/3) feet per second.

To cover 360 ft at 25 mph, it would take

                360 ft / (36 and 2/3 ft/sec)  =   9.82 seconds .

Anybody who covers the 360 feet in less than 9.82 seconds
is moving faster than 25 mph.
_________________________________

If you're interested, here's how to do it in the other direction:

Let's say a car covers the 360 feet in ' S ' seconds.
What's the speed of the car ?

           (360 ft / S sec) · (1 mile / 5280 feet) · (3600 sec/hour)

       =    (360 · 3600) / (S · 5280)  mile/hour

       =        245.5 / S    miles per hour .

The teacher timed one car crossing both strips in 7.0 seconds.
How fast was that car traveling ?

                   245.5 / 7.0  =  35.1 miles per hour


Another teacher timed another car that took 9.82 seconds to cross
both strips.  How fast was this car traveling ?

                        245.5 / 9.82  =  25 miles per hour
7 0
3 years ago
Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.
igor_vitrenko [27]

Answer:

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7

So, the solution of the equation is

y = Ae^{m_{1} t} + Be^{m_{2} t}

where m₁ = 3 and m₂ = -7.

So,

y = Ae^{3t} + Be^{-7t}

Also,

y' = 3Ae^{3t} - 7e^{-7t}

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1      (1)

y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}

Substituting A into (1) above, we have

\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1      \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}

Substituting B into A, we have

A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}

Substituting A and B into y, we have

y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

So the solution to the differential equation is

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

6 0
3 years ago
PLSSSS HELP GIVING 5 POINTS PLUS BRAINLIEST
Reil [10]

Answer:

its c or a but i think its mostly a

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A point located at (0, -6) is the same distance from 0 as the point located at (0, 6).
torisob [31]
True. because it is still 6 away from 0 no matter what way you go
7 0
3 years ago
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