How do I do this I need help I don’t wanna fail this quarter!!!!

Triangle PQR is similar to triangle XYZ Select all angles that have a cosine of 9/15

kotegsom [21]

Answer:

Step-by-step explanation:

4 0

3 years ago

Please help, the questions are now attached

Snowcat [4.5K]

A- the answer is 2, because it has the most amount of crosses or is the highest bar, showing that it is the most popular (mode)

mean is adding all the numbers divided by how many numbers there are, so 20/10=2

median is the number in the middle of an (ordered) row. but since the numbers are already ordered, it is in between 33 and 35, so the median is 34

C and D since they both show the most and least popular result, rather than estimating percentages.

D because each sample adds up to 200.

8 0

4 years ago

Read 2 more answers

Roger gets $40 per day as wages and $4.50 as commission for every pair of shoes he sells in a day. His daily earnings goal is $1

Bingel [31]

Answer:

40 + 4.50x =112

4.5x = 72

x =16

Step-by-step explanation:

pls mark me as brainlest

5 0

3 years ago

Read 2 more answers

One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number o

Zielflug [23.3K]

To be clear, the given relation between time and female population is an integral:
 $t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,
dP$

The problem says that r = 1.2 and S = 400, therefore substituting:
 $t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]}
} \, dP$ 

= $
\int { \frac{P+400}{P(0.2P - 400)} } \, dP$

In order to evaluate this integral, we need to write this rational function in a simpler way:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} +
\frac{B}{(0.2P - 400)}$ 

where we need to evaluate A and B. In order to do so, let's calculate the LCD:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P -
400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)}$ 

the denominators cancel out and we get:
P + 400 = 0.2AP - 400A + BP
 = P(0.2A + B) - 400A

The two sides must be equal to each other, bringing the system:
 $\left \{ {{0.2A + B = 1} \atop {-400A =
400}} \right.$ 

Which can be easily solved:
 $\left \{ {{B=1.2} \atop {A=-1}} \right.$ 

Therefore, our integral can be written as:
 $t = \int { \frac{P+400}{P(0.2P - 400)} } \,
dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP$ 
= $- \int { \frac{1}{P} \, dP +
1.2\int { \frac{1}{0.2P-400} } \, dP$ 
= $- \int { \frac{1}{P} \, dP +
6\int { \frac{0.2}{0.2P-400} } \, dP$ 
= - ln |P| + 6 ln |0.2P - 400| + C

Now, let’s evaluate C by considering that at t = 0 P = 10000:
0 = - ln |10000| + 6 ln |0.2(10000) - 400| + C
C = ln |10000| - 6 ln |1600|
C = ln (10⁴) - 6 ln (2⁶·5²)
C = 4 ln (10) - 36 ln (2) - 12 ln (5) 
 Therefore, the equation relating female population with time requested is:
t = - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln (2) - 12 ln (5)

8 0

3 years ago

Gina has an meeting in 45 min. She is driving at a rate of 30 mi/h. If she is 24 mi away, will she arrive on time? If not, how e

dsp73

Gina will be late because she's still missing 1.5 miles

7 0

3 years ago