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romanna [79]
3 years ago
7

what happens to the yield of hydrogen if the reaction is carried out at a higher pressure but at the same temperature​

Chemistry
1 answer:
ikadub [295]3 years ago
3 0

Answer:

The yield of hydrogen decreases

Explanation:

The Haber process is exothermic. The equation of the Haber process is;

N2(g) + 3H2(g) --------> 2NH3(g)    ΔH = -ve

Now, if we maintain a constant temperature, the number of volumes will affect the yield of products as follows;

The higher the pressure the lesser yield of hydrogen because the increase in pressure shifts the equilibrium position towards the right hand side.

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Research help?
prisoha [69]

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They enable browning.

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Explanation:

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The structure of 3-propylpentane is best described as
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Calculate the energy per photon (in J) associated with a frequency of 1260 kHz. Submit answer in scientific notation using the f
aniked [119]

Taking into account the definition of photon and energy of a photon, the energy per photon is 8.3538×10⁻³⁸ J.

<h3>Energy of a photon</h3>

Electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absortion, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".

The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.

The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression:

E=h×f

where:

  • E is the energy of a photon.
  • h is the Planck's constant h.
  • f is the frequency of electromagnetic radiation.

<h3>Energy per photon</h3>

In this case, you know:

  • h=  6.63*10⁻³⁴ Js
  • f= 1260 kHz= 1,260,000 Hz= 1.26×10⁶ Hz (being 1 kHz=1000 Hz)

Replacing in the definition of energy of a photon:

E= 1.26×10⁶ Hz× 6.63×10⁻³⁴ Js

<u><em>E= 8.3538×10⁻³⁸ J</em></u>

Finally, the energy per photon is 8.3538×10⁻³⁸ J.

Learn more about energy of a photon:

brainly.com/question/8924116

brainly.com/question/6945706

brainly.com/question/8000078

#SPJ1

6 0
2 years ago
Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Ide
olya-2409 [2.1K]

Answer:

     strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

     X^{+} will oxidize Z

Explanation:

The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.

Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.

Order of reduction potential:

                       E_{X^{+}\mid X}^{0}(1.52V)> E_{Z^{3+}\mid Z}^{0}(0.84V)> E_{Y^{2+}\mid Y}^{0}(-1.17V)

So, strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

As reduction potential of the half cell X^{+}\mid X is higher than the reduction potential of the half cell Z^{3+}\mid Z therefore X^{+} will oxidize Z into Z^{3+} and itself gets converted into X.

     

5 0
3 years ago
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