Atmospheric
pressure<span>, sometimes also called barometric pressure, is the pressure exerted by the weight of air in
the </span>atmosphere of Earth<span> (or that of another planet)</span>
1 atm is equivalent to = 101325
Pa
= 760 mmHg
= 760 torr
= 1.01325 bar
So 1.23 atm is equal to
= 124629.8 Pa
= 934.8 mmHg
= 934.8 torr
<span>= 1.2462 bar</span>
The metals will lose electrons while the non metals will gain electrons in order to attain octet structure.
An ion can be cation (positively charged) or anion (negatively charged).
Cations attain octet structure (8) by losing electron(s) while anions become stable or attains octet structure (8) by gaining electron(s).
The remaining elements are completed as follows to attain octet structure;
<u>Element</u>--<u>valence electron</u>--<u>electrons to gain</u>--<u>electrons to lose</u>--<u>ion formed</u>
O ------------ 6 ---------------------- 2 ------------------------ none -------------- ![O^{2-}](https://tex.z-dn.net/?f=O%5E%7B2-%7D)
Ca -------- 2 ----------------------- none ---------------------- 2 ------------------ ![Ca^{2+}](https://tex.z-dn.net/?f=Ca%5E%7B2%2B%7D)
Br ----------- 7 --------------------- 1 ------------------------ none --------------- ![Br^{-}](https://tex.z-dn.net/?f=Br%5E%7B-%7D)
S ------------ 6 ----------------------- 2 ------------------------ none --------------- ![S^{2-}](https://tex.z-dn.net/?f=S%5E%7B2-%7D)
Cl ------------ 7 ----------------------- 1 ------------------------ none ----------------![Cl^{-}](https://tex.z-dn.net/?f=Cl%5E%7B-%7D)
K -------------- 1 ----------------------- none ----------------------- 1 ------------------ ![K^{+}](https://tex.z-dn.net/?f=K%5E%7B%2B%7D)
Mg ------------ 2 ---------------------- none ---------------------- 2 ---------------- ![Mg^{2+}](https://tex.z-dn.net/?f=Mg%5E%7B2%2B%7D)
Be ------------- 2 ---------------------- none ---------------------- 2 ---------------- ![Be^{2+}](https://tex.z-dn.net/?f=Be%5E%7B2%2B%7D)
Learn more here: brainly.com/question/21089350
Answer:
metals donate electrons to nonsmetals
Answer : The average atomic mass of chlorine is, 32.37 amu
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
![\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20%7D%3D%5Csum_%7Bi%3D1%7D%5En%5Ctext%7B%28Atomic%20mass%20of%20an%20isotopes%29%7D_i%5Ctimes%20%5Ctext%7B%28Fractional%20abundance%7D%29_i)
As we are given that,
Mass of isotope 1 = 34.97 amu
Percentage abundance of isotope 1 = 75.77 %
Fractional abundance of isotope 1 = 0.7577
Mass of isotope 2 = 36.97 amu
Percentage abundance of isotope 2 = 24.23 %
Fractional abundance of isotope 2 = 0.2423
Now put all the given values in above formula, we get:
![\text{Average atomic mass of element}=\sum[(34.97\times 0.7577)+(24.23\times 0.2423)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D%5Csum%5B%2834.97%5Ctimes%200.7577%29%2B%2824.23%5Ctimes%200.2423%29%5D)
![\text{Average atomic mass of element}=32.37amu](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D32.37amu)
Therefore, the average atomic mass of chlorine is, 32.37 amu