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Travka [436]
3 years ago
10

Find the missing terms in each of the ​

Mathematics
1 answer:
zubka84 [21]3 years ago
8 0
1.29,31
2.42,47
3.81,69
4.50,36
5.7,16
6.26,30
7.15,23
8.28,34
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The chicken increased by $0.98, from $6.50 to $7.48. What is the percent change in the cost of this meal? Show your proportion a
ryzh [129]

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Step-by-step explanation:you have a blessed thanksgiveing

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Draw a rectangle that has an area of 8 units square and a perimeter of 12 units. What are the side lengths
choli [55]

Answer:

4 by 2

Step-by-step explanation:

you can basically guess and check with this question but I knew if it was a rectangle then 2 sides would be larger than the other. So I started off figuring out what times what equals 8 and I got 2 and 4. So I put those in for the side lengths and I got 12.

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Help, middle school homework
Vesna [10]
The answer is 180°

Angles between straight lines are 180°

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3 years ago
Which ordered pairs are solutions to the inequality y - 3x < -8?
7nadin3 [17]

Answer:

Option B,C and E are solution to given inequality y - 3x < -8

Step-by-step explanation:

We need to check which ordered pairs from given options satisfy the inequality y - 3x < -8

Ordered pairs are solutions to inequality if they satisfy the inequality

Checking each options by pitting values of x and y in given inequality

A ) (1, -5)

-5-3(1)

So, this ordered pair is not the solution of inequality as it doesn't satisfy the inequality.

B) (-3, - 2)

-2-3(-3) < -8\\-2-9

So, this ordered pair is solution of inequality as it satisfies the inequality.

C) (0, -9)

-9-3(0)

So, this ordered pair is solution of inequality as it satisfies the inequality.

D) (2, -1)

-1-3(2)

So, this ordered pair is not the solution of inequality as it doesn't satisfy the inequality.

E) (5, 4)​​​

4-3(5)

So, this ordered pair is solution of inequality as it satisfies the inequality.

So, Option B,C and E are solution to given inequality y - 3x < -8

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2 years ago
Find the quotient. n^4/n^5
zhenek [66]
Reduce the expression by cancelling the common factors: 1/n
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