D doesn't make much sense, it's valid, but not what we're looking for. B also has a correlation with D, same reasoning applies. As for A, it seems pretty legit, but I don't believe that's what we're looking for.
Choice C is the most obvious one though. We're talking about a network and as may or may not know it's a wireless one in a manner of speaking. A <span>couple of computers in the network that have trouble maintaining a signal will indefinitely lead to failure of a network since both the links and nodes of certain computer systems are incapable of maintaining a signal. </span>
Hi,
I changed your program using some of the concepts you were trying to use. Hopefully you can see how it works:
#include <string>
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
short T;
cin >> T;
cin.ignore();
string str[100];
for(int i=0; i<T; i++)
{
getline(cin, str[i]);
}
for (int i = 0; i < T; i++)
{
stringstream ss(str[i]);
string tmp;
vector<string> v;
while (ss >> tmp)
{
// Let's capitalize it before storing in the vector
if (!tmp.empty())
{
transform(begin(tmp), end(tmp), std::begin(tmp), ::tolower);
tmp[0] = toupper(tmp[0]);
}
v.push_back(tmp);
}
if (v.size() == 1)
{
cout << v[0] << endl;
}
else if (v.size() == 2)
{
cout << v[0][0] << ". " << v[1] << endl;
}
else
{
cout << v[0][0] << ". " << v[1][0] << ". " << v[2] << endl;
}
}
return 0;
}
Answer:
The disk is a removable disk.
