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3 years ago

Uber drivers are considered 'independent contractors' and thus can apply for business licenses.

2 answers:

8 0

True, Uber drivers can be deactivated/fired if they ratings reach a certain point, despite the fact they are still considered “independent contractors”. They still belong to a company.

Natasha2012 [34]3 years ago

4 0

I’m pretty sure it’s true!

You might be interested in

Chemical engineering got is unofficial start around the time of the __________ __________ ________.

Yuri [45]

World war II i think

6 0

4 years ago

What is the definition of a struck by injury

dmitriy555 [2]

Produced by forcible contact or impact between the injured person and an object or a piece of equipment

Explanation:

it mean you get injured after you've already been injured

3 0

3 years ago

The disk of radius 0.4 m is originally rotating at ωo=4 rad/sec. If it is subjected to a constant angular acceleration of α=5 ra

Lina20 [59]

Answer:32.4m/ $s^2$

Explanation:

Given data

$radius\left ( r\right )$ =0.4m

Intial angular velocity $\left ( \omega_0\right )$ =4rad/s

angular acceleration $\left ( \alpha\right )$ =5rad/ $s^2$

angular velocity after 1 sec

$\omega$ = $\omega_0$ + $\alpha\times\t$

$\omega$ =4+5 $\left ( 1\right )$

$\omega$ =9rad/s

Velocity of point on the outer surface of disc $\left ( v\right )$ = $\omega_0\timesr$

v= $9\times0.4$ m/s=3.6m/s

Normal component of acceleration $\left ( a_c\right )$ = $\frac{v^2}{r}$

$a_c$ = $\frac{3.6\times3.6}{0.4}$ =32.4m/ $s^2$

3 0

4 years ago

For each of the cases below, determine if the heat engine satisfies the first law (energy equation) and if it violates the secon

stepan [7]

Answer:

From first law of thermodynamics(energy conservation)

Qa= Qr+W

Qa=Heat added to the engine

Qr=heat rejected from the engine

W=work output from the engine

Second law:

It is impossible to construct a heat engine that will deliver the work with out rejecting heat.

In other word ,if engine take heat then it will reject some amount heat and will deliver some amount of work.

QH=6 kW,

QL=4 kW,

W=2 kW

6 KW= 4 + 2 KW

It satisfy the first law.

Here heat is also rejected from the engine that is why it satisfy second law.

QH=6 kW, QL=0 kW, W=6 kW

This satisfy first law but does not satisfy second law because heat rejection is zero.

QH=6 kW , QL=2 kW, W=5 kW

This does not satisfy first as well as second law.Because summation of heat rejection and work can not be greater than heat addition or we can say that energy is not conserve.

QH=6 kW, QL=6 kW, W=0 kW

This satisfy first law only and does not satisfy second law.

6 0

3 years ago

A jet aircraft is in level flight at an altitude of 30,000 ft with an airspeed of 500 ft/s. The aircraft has a gross weight of 1

Naily [24]

Answer:

a) attached below

b) 0.0337

c) 2730.206 Ib

d) 2320.338 ft/min

Explanation:

<u>a) Plot of the drag polar for this aircraft </u>

first we will calculate :

Wing area (s) = Wing span (b) * Average chord length(c)

= 53.3 * 6 = 319.8 ft^2

Aspect ratio = b^2 / s = 8.883

K = 1 / $\pi$ eAR = 1 /

Drag polar ( Cd ) = 0.02 + 0.044 C^2L

attached below is a plot of the drag polar

<u />

Attached below is the detailed solution of the remaining part of the question

6 0

3 years ago