Answer:
hello some data related to your question is missing attached below is the missing data
answer : 63700 Ib/hr
Explanation:
Given data :
Limestone mix : consists of 94% CaCO3 and 6% inert material
Actual feed rate = 36,000 Ib/hr
SO2 in flue gas = 20,314 Ib/hr
FGD efficiency = 97%
resulting sludge contains 58% solids
<u>Calculate the Total sludge production rate </u>
First : determine SO2 removed in sludge
= 0.97 * 20314
= 19704.58 Ib/hr
next : moles of SO2 removed
= 19704.58 / 64 Ib/ Ib mol
= 307.88 Ib mol / hr
also moles of CaSO3 produced = 307.88 Ib mol / hr
mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr
Therefore Total sludge production rate
= 36946.09 / 0.58
= 63700.15 Ib/hr
<u />
<u />
<u />
<u />
Explanation:
first changing kilo ohm to ohm
860000 = 860 kΩ
and change 34 micro ampare to ampare
34 μA=3.4×10^-5
recalling the equation V=I*R
V= 3.4×10^-5×860000
v=29.24
Answer:
a) 0.697*10³ lb.in
b) 6.352 ksi
Explanation:
a)
For cylinder AB:
Let Length of AB = 12 in
For cylinder BC:
Let Length of BC = 18 in
b) Maximum shear stress in BC
Maximum shear stress in AB
Answer:
using calculations Heat losses will be 4512 J
