1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dvinal [7]
2 years ago
12

How to build a laser pointer?

Engineering
1 answer:
zepelin [54]2 years ago
6 0

Answer:

It's easier to buy one, but you can search for a tutorial on how to make one on Yuotube.

There are quite a few videos on how to make one.

You might be interested in
A teenage brain is already fully developed to enable us to manage risks effectively.
Kisachek [45]

Answer:

false

Explanation:

the brain is only really fully devolved by age 26

3 0
2 years ago
Read 2 more answers
An alloy is evaluated for potential creep deformation in a short-term laboratory experiment. The creep rate (ϵ˙) is found to be
cupoosta [38]

Answer:

Activation energy for creep in this temperature range is Q = 252.2 kJ/mol

Explanation:

To calculate the creep rate at a particular temperature

creep rate, \zeta_{\theta} = C \exp(\frac{-Q}{R \theta} )

Creep rate at 800⁰C, \zeta_{800} = C \exp(\frac{-Q}{R (800+273)} )

\zeta_{800} = C \exp(\frac{-Q}{1073R} )\\\zeta_{800} = 1 \% per hour =0.01\\

0.01 = C \exp(\frac{-Q}{1073R} ).........................(1)

Creep rate at 700⁰C

\zeta_{700} = C \exp(\frac{-Q}{R (700+273)} )

\zeta_{800} = C \exp(\frac{-Q}{973R} )\\\zeta_{800} = 5.5 * 10^{-2}  \% per hour =5.5 * 10^{-4}

5.5 * 10^{-4}  = C \exp(\frac{-Q}{1073R} ).................(2)

Divide equation (1) by equation (2)

\frac{0.01}{5.5 * 10^{-4} } = \exp[\frac{-Q}{1073R} -\frac{-Q}{973R} ]\\18.182= \exp[\frac{-Q}{1073R} +\frac{Q}{973R} ]\\R = 8.314\\18.182= \exp[\frac{-Q}{1073*8.314} +\frac{Q}{973*8.314} ]\\18.182= \exp[0.0000115 Q]\\

Take the natural log of both sides

ln 18.182= 0.0000115Q\\2.9004 = 0.0000115Q\\Q = 2.9004/0.0000115\\Q = 252211.49 J/mol\\Q = 252.2 kJ/mol

3 0
3 years ago
A sports car has a drag coefficient of 0.29 and a frontal area of 20 ft2, and is travelling at a speed of 120 mi/hour. How much
Andrej [43]

Answer:

Power required to overcome aerodynamic drag is 50.971 KW

Explanation:

For explanation see the picture attached

4 0
3 years ago
Can someone pls give me the answer to this?
olganol [36]

I think option c 12 is currect

7 0
3 years ago
Select the correct answer.
FrozenT [24]

Answer:

B. Italy

Explanation:

Hope this helps :)

6 0
3 years ago
Read 2 more answers
Other questions:
  • The yield of a chemical process is being studied.The two most important variables are thought to be the pressure and the tempera
    9·1 answer
  • You are given a partial implementation of one header file, GildedRose.hpp. Item is a class that holds the information for each i
    6·1 answer
  • What does CADCAM stand for ?
    10·2 answers
  • For a steel alloy it has been determined that a carburizing heat treatment of 14 h duration at 809°C will raise the carbon conce
    13·1 answer
  • The equation for the velocity V in a pipe with diameter d and length L, under laminar condition is given by the equation V=Δpdsq
    10·1 answer
  • Employees cannot be held legally responsible for an environmental violation.
    14·1 answer
  • Advanced manufacturing does NOT serve the transportation, communications, or medical industries. Is this statement TRUE or FALSE
    11·2 answers
  • CNG is a readily available alternative to _________.
    9·1 answer
  • Task Three :Write a C++ program to read temperature
    15·1 answer
  • Drivers education :Anything that draws your mind off driving is
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!