Answer:
The advantage to using a rosebud tip is that it expands the flame temperature over a wider area vs using a #0 size tip.
Explanation:
Hope this helped Mark BRAINLIEST!!
Answer:
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Answer:
the work required by a reversible pump operating with the same conditions, in kW is 16.39 kW
the isentropic pump efficiency is 78%
Explanation:
Given that;
m = 1.2 kg/sec
T = 50 degree Celsius { Vf = 0.001012 m^3/kg}
P1 = 1.5 Mpa
P2 = 15 Mpa
W-actual = 21 kw
W reversible = m*Vf (p2 - p1)
= 1.2 * 0.001012 * ( 15*10^3 - 1.5*10^3)
= 1.2 * 0.001012 * 13500
= 16.39 kW
the work required by a reversible pump operating with the same conditions, in kW is 16.39 kW
Isentropic Pump efficiency = W-reversible / W-actual
= 16.39 / 21 = 0.78
= 78%
the isentropic pump efficiency is 78%
Answer:
The answer is VN =37.416 m/s
Explanation:
Recall that:
Pressure (atmospheric) = 100 kPa
So. we solve for the maximum velocity (m/s) to which water can be accelerated by the nozzles
Now,
Pabs =Patm + Pgauge = 800 KN/m²
Thus
PT/9.81 + VT²/2g =PN/9.81 + VN²/2g
Here
Acceleration due to gravity = 9.81 m/s
800/9.81 + 0
= 100/9.81 + VN²/19.62
Here,
9.81 * 2= 19.62
Thus,
VN²/19.62 = 700/9.81
So,
VN² =1400
VN =37.416 m/s
Note: (800 - 100) = 700