Answer:
The displacement from t = 0 to t = 10 s, is -880 m
Distance is 912 m
Explanation:
. . . . . . . . . . A
integrate above equation we get

from information given in the question we have
t = 1 s, s = -10 m
so distance s will be
-10 = 12 - 1 + C,
C = -21

we know that acceleration is given as
[FROM EQUATION A]
Acceleration at t = 4 s, a(4) = -24 m/s^2
for the displacement from t = 0 to t = 10 s,

the distance the particle travels during this time period:
let v = 0,

t = 2 s
Distance ![= [s(2) - s(0)] + [s(2) - s(10)] = [1\times 2 - 2^3] + [(12\times 2 - 2^3) - (12\times 10 - 10^3)] = 912 m](https://tex.z-dn.net/?f=%3D%20%5Bs%282%29%20-%20s%280%29%5D%20%2B%20%5Bs%282%29%20-%20s%2810%29%5D%20%3D%20%5B1%5Ctimes%202%20-%202%5E3%5D%20%2B%20%5B%2812%5Ctimes%202%20-%202%5E3%29%20-%20%2812%5Ctimes%2010%20-%2010%5E3%29%5D%20%3D%20912%20m)
Answer:Non-uniform motion
Explanation:
This is an example of Non-uniform motion because unequal distance traveled by an object in equal interval of time is termed as Non-Uniform motion and here also the distance traveled by object is 1 ft ,4 ft and 8 ft which is different from each other.
In Uniform motion distance traveled is equal in equal interval of time .
Answer:112.376 s
Explanation:
Given






Using Newton's law of cooling
=
=
7=
Taking log both side
t=112.376sec
Answer:
A continuity test
Explanation:
A continuity test is used to verified that current will flow in an electrical circuit, it performed by placing a small voltage across the chosen path. continuity test ensure that the equipment grounding conductor is electrically continuous and this test is perform on all the cord sets, receptacles that aren't part of a building or structure's permanent wiring, and cord-and-plug connected equipment required to be grounded. example of equipment used in testing current flow in continuity test are Analog multi-meter, voltage/continuity tester etc.
Continuity test and terminal connection test are the two test required by OSHA on all electrical equipment
Answer:
answer is D
Explanation:
comparing the spending habits of two different families.