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2 years ago

A crankcase heater is often used to prevent refrigerant from mixing with compressor oil during periods of:

Engineering

2 answers:

andrew-mc [135]2 years ago

8 0

Answer:

Low ambient temperature

I think that it low ambent temparture because of what they said

stira [4]2 years ago

5 0

Answer:

Low ambient temperature

Explanation:

Hope this helps. If it did, please mark as brianliest so other people see it. Thanks! - Kai

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This manometer is used to measure the difference in water level between the two tanks.

SpyIntel [72]

Answer:

a) True

Explanation:

hope it helps u

3 0

2 years ago

A machine raises 20kg of water through a height of 50m in 10secs. What is the power of the machine.

Tomtit [17]

Answer:

hhahhhwghwhwhwhwjwnwjnnnnwnwwnw

Explanation:

jwkwkkwoiwiwiwiwiwowwiwowowiiiiwuuwuwgeevehehsvhsvwhbhhehehwgjjwhwhjwjqwjjuuuwi####!\\\\e

5 0

2 years ago

A ballistic pendulum consists of a 3.60 kg wooden block on the end of a long string. From the pivot point to the center‐of‐mass

Pavel [41]

Answer:

17.799°

Explanation:

When the bullet hits the block at that time the momentum is conserved

So, initial momentum = final momentum

$P_i=P_f$

So $28\times 10^{-3}\times 210=(3.6+0.028)v_f$

$v_f=1.6207\ m/sec$

Now energy is also conserved

So $\frac{1}{2}\times (3.6+0.028)\times 1.6207^2=(3.6+0.028)\times 9.81\times 2.8(1-cos\Theta )$

$cos\Theta =0.8521So\ \Theta =17.799^{\circ}$

3 0

2 years ago

How fast is a 2012 nissan sentra<br>speed and acceleration

Alika [10]

Answer:

it has 15 horsepower to 300 horsepower and it weighs 2,906 to 3,131

Explanation:

its torque is 142 to 180

it has a inline 4 engine

there's a SE-R which has a turbo

4 0

3 years ago

Water flows steadily through the pipe as shown below, such that the pressure at section (1) and at section (2) are 300 kPa and 1

steposvetlana [31]

Answer:

The velocity at section is approximately 42.2 m/s

Explanation:

For the water flowing through the pipe, we have;

The pressure at section (1), P₁ = 300 kPa

The pressure at section (2), P₂ = 100 kPa

The diameter at section (1), D₁ = 0.1 m

The height of section (1) above section (2), D₂ = 50 m

The velocity at section (1), v₁ = 20 m/s

Let 'v₂' represent the velocity at section (2)

According to Bernoulli's equation, we have;

$z_1 + \dfrac{P_1}{\rho \cdot g} + \dfrac{v^2_1}{2 \cdot g} = z_2 + \dfrac{P_2}{\rho \cdot g} + \dfrac{v^2_2}{2 \cdot g}$

Where;

ρ = The density of water = 997 kg/m³

g = The acceleration due to gravity = 9.8 m/s²

z₁ = 50 m

z₂ = The reference = 0 m

By plugging in the values, we have;

$50 \, m + \dfrac{300 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{(20 \, m/s)^2}{2 \times 9.8 \, m/s^2} = \dfrac{100 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{v_2^2}{2 \times 9.8 \, m/s^2}$ 50 m + 30.704358 m + 20.4081633 m = 10.234786 m + $\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}$

50 m + 30.704358 m + 20.4081633 m - 10.234786 m = $\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}$

90.8777353 m = $\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}$

v₂² = 2 × 9.8 m/s² × 90.8777353 m

v₂² = 1,781.20361 m²/s²

v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s

The velocity at section (2), v₂ ≈ 42.2 m/s

3 0

2 years ago