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gavmur [86]
3 years ago
6

How many electrons does Rb1- have?

Chemistry
1 answer:
OLEGan [10]3 years ago
5 0

Answer:

Explanation:

Anywhere you go, I'll go

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Got, got chemistry

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Any time or place, no shame

You got my attention now

Can anybody ride my wave the same

You know what I'm talkin' about

Hit you with some truth

You're like a dream

I wanna believe

Hit you with some truth

When we're together

I can't even lie

You and me got chemistry

Got, got chemistry

Got chemistry

Feel it when you're close to me

And out of reach

And in between

We got la la la, lots of good vibrations

We got la la la, we got la la la

You and me got chemistry

Got, got chemistry

Got chemistry

You and me got, you and me got

You and me got chemistry, got, got chemistry,

Got chemistry

Feel it when you're close to me

And out of reach

And in between

Ohh we got chemistry

Feel it when you're close to me

And out of reach

And in between

Ohh, we got la, la, la, we got lots of good vibrations

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You and me got chemistry, got, got chemistry,

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'Cause you and me got

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A voltaic cell is constructed in which the anode is a Fe|Fe2 half cell and the cathode is a Cd|Cd2 half cell. The half-cell comp
Svetradugi [14.3K]

Answer: The Anode reaction is Fe(s)\rightarrow Fe^{2+}(aq)+2e^-

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons.Oxidation occurs at anode.

Anode : Fe(s)\rightarrow Fe^{2+}(aq)+2e^-

Reduction reaction is defined as the reaction in which a substance gains electrons. Reduction occurs at cathode.

Cathode : Cd^{2+}(aq)+2e^-\rightarrow Cd(s)

3 0
3 years ago
An aqueous nacl solution is made using 112 g of nacl diluted to a total solution volume of 1.00 l. calculate the molarity, molal
worty [1.4K]
Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl  = NaCl mass present / molar mass of NaCl 
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol 
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol 
therefore molarity of NaCl is 1.91 M

Q2) 
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume. 
density of the solution is 1.08 g/mL. 
therefore mass of the solution is = density x volume 
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent 
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol 
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg


Q3) 
mass percentage is the percentage of mass of solute by total mass of the solution 
mass percentage of solution = mass of solute / total mass of the solution 
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %
5 0
3 years ago
The number of hydrogen ions would equal the number of hydroxide ions in a solution with a pH of what?
Dafna1 [17]

Seven. It's a neutral pH.

6 0
3 years ago
Consider this reaction: 3Fe2O3(s) + CO(g) → 2Fe3O4(s) + CO2(g).
telo118 [61]
The rate<span> of a </span>reaction increases<span> if the temperature is increased, the concentration of a dissolved reactant is increased and the pressure of a </span>reacting<span> gas is increased. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
4 0
3 years ago
Read 2 more answers
What is the oxidation state of S in so ??​
Marina86 [1]

Answer:

+2

Explanation:

If a compound SO existed, we would identify the oxidation state of sulfur using the following logic:

  • oxygen is more electronegative than sulfur, so it's more electron-withdrawing and it should have a negative oxidation state producing a positive oxidation state for sulfur;
  • oxygen typically has an oxidation state of -2;
  • we may then apply the fact that SO is expected to be a molecule with a net charge of 0;
  • if the net charge is 0 and the oxidation state of oxygen is -2, we may set the oxidation state of S to x;
  • write the equation for the net charge of 0 by adding all individual charges of the two atoms: x + (-2) = 0;
  • hence, x = 2.

That said, in this hypothetical compound S would have an oxidation state of +2.

6 0
3 years ago
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