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galina1969 [7]
3 years ago
11

When was that one moment when you laughed the hardest

Chemistry
2 answers:
kolezko [41]3 years ago
7 0

Answer:

last month!!

it was on yt

Andrei [34K]3 years ago
4 0

Answer:

My weightlifting coaches are all gay for each other and its hilarious to see 3 large buff men play fighting and wrestling around the weight room.

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70.906 g/mol

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Which of the following is an important application of hydrogen bonding
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5 0
2 years ago
A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The
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Answer:- Heat lost by the metal is 279.45 cal.

Solution:- This type of problems are solved by using the concept, heat given = - heat taken

Metal temperature is decreasing from 45.00 degree C to 11.08 degree C. It means the heat is lost by the metal and this heat lost by metal is gained by water and the calorimeter to raise their temperature.

the equation we use is, q=mc\Delta T .

where, q is the heat energy, m is mass, c is specific heat and \Delta T is change in temperature.

Combined mass of calorimeter and water is 250.0 g and the specific heat is \frac{1.035cal}{g.^0C} .

\Delta T  for calorimeter and water (combined) = 11.08 - 10.00 = 1.08 degree C

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let's plug in the values in the above equation and calculate heat gained by combined system.

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q = 279.45 cal

So, the heat lost by the metal is 279.45 cal.


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3 years ago
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