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Misha Larkins [42]
3 years ago
15

If you determined that the volume of a silver bar is 100. mL, how many atoms of silver would be in the bar? The density of silv

er is 10.5 g/mL.
Chemistry
2 answers:
g100num [7]3 years ago
7 0
D = m/v
m = Dv = 10.5 * 100 = 1050 grams
1050/Ag's amu = 1050/47 = around 22.5
22.5 moles is your answer
Naya [18.7K]3 years ago
4 0
I think it might be 6.321E26 because if you multiply 100ml by 10.5 g and 6.02E23, thats what you get
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If a 500 ml sample of water contains 2.6 x 10-6 g of iron, what is the concentration of iron in ppb?
Anastasy [175]

The concentration of iron in ppb is 5.2 ppb

In atmospheric chemistry, PPM( parts per million) and PPB( parts per billion) units are used to express the concentration of gases. PPB stands for parts per billion, while PPM stands for parts of gas per million parts of air.

2.6 × 10⁻⁶ grams of iron in 500 ml of water.

Now, converting milliliter into liter:

500 mL = 500 mL × ( 1L / 1000 mL ) = 0.5 L

Now for ppm, mass must be in mg.

2.6 × 10⁻⁶ grams = 2.6 × 10⁻⁶ grams × ( 1000 mg / 1 grams ) = 2.6 × 10⁻³ mg

Then, the concentration of iron in ppm will be:

2.6 × 10⁻³ mg / 0.5 L = 5.2 × 10⁻³ ppm

Now, 1 ppm = 1000 ppb

Therefore,

5.2 × 10⁻³ ppm × 10³ = 5.2 ppb

Learn more about concentration here:

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8 0
1 year ago
(IMAGE) Name the following carboxylic acid: CH3CH2COOH​
yKpoI14uk [10]

Answer:

Propanoic acid

option D is correct answer

5 0
3 years ago
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When the drug heroin comes into contact with the Marquis reagent chemical what happens?
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When it comes into contact with It will turn purple
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3 years ago
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PLEASE HELP!!!!!!!!!!!
Amiraneli [1.4K]

Answer:

I believe your answer would be grams.

4 0
2 years ago
HELP ASAP PLZ!!!! Find the mass of each substance. Show your work.
Gemiola [76]

Answer:

A. m C5H12 = 108.23 g

B. m F2 = 547.142 g

C. m Ca(CN)2 = 71.85 g

Explanation:

  • mass (m) = mol (n) × molecular weigth (Mw)

∴ Mw C5H12 = ((12.011)(5)) + ((1.008)(12)) = 72.151 g/mol C5H12

∴ Mw F2 = (18.998)(2) = 37.996 g/mol F2

∴ Mw = Ca(CN)2 = 40.078+((12.011+14.007)(2)) = 92.114 g/mol Ca(CN)2

A. m C5H12 = ( 1.50 mol)×(72.151 g/mol) = 108.23 g C5H12

B. m F2 = (14.4 mol)×(37.996 g/mol) = 547.142 g F2

C. m Ca(CN)2 = (0.780 mol)×(92.114 g/mol) = 71.85 g Ca(CN)2

8 0
3 years ago
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