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Alexandra [31]
3 years ago
8

Carmen swam 2 1/3 laps in 3 1/2 minutes. Assume she swam the entire time at the same rate. What was her speed in laps per minute

Mathematics
1 answer:
kifflom [539]3 years ago
8 0
Her speed is .266 of a lap per min.
Scale back to unit rate (per sec) then up to 60 sec (min)
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Hey I need helping with solving thank you
Marrrta [24]

Answer:

the answer to this equation is c (10)

6 0
3 years ago
If 4 is added to double the number n, the result is the same as
svlad2 [7]
I think it’s A because 4*2 is 8 and if n were quadrupled it would be 2
6 0
3 years ago
Read 2 more answers
Omega House Family restaurant is midway between Forsyth Tech Community College
Veseljchak [2.6K]

The coordinates of Omega house is (3/2, 1)

Data;

  • Forsyth Tech = (7,-5)
  • Stadium = (-4, 3)

<h3>Midpoint of a Line</h3>

To find the coordinates of Omega house, we can use the formula of midpoint of a line since Omega house falls between Forsyth Tech and Stadium

x,y = (\frac{x_1+ x_2}{2} , \frac{y_1+y_2}{2})

We can substitute the values and solve for both x and y coordinates.

x = \frac{x_1+x_2}{2} \\x = \frac{7 + (-4)}{2} = \frac{3}{2}

The value of the y-coordinate is

y = \frac{-5+ 3}{2} = 1

The coordinates of Omega house is (3/2, 1)

Learn more on midpoint of a line here;

brainly.com/question/5901621

4 0
3 years ago
I WILL MARK BRAINLIEST PLEASE HELP FIND ANGLE DEB <br><br> ITS DUE AT 12 PLEASE HELP PLEASE
Gemiola [76]

Answer:

\boxed {\boxed {\sf \angle DEB = 111 \textdegree}}

Step-by-step explanation:

We want to find angle DEB. We know AB is perpendicular to AC, CD is congruent to CE and angle B is 48 degrees.

ABC is a triangle. The angles in a triangle must add up to 180 degrees. Therefore:

  • ∠A+∠B+∠C= 180°

We know two angles: ∠B= 48° and ∠A= 90° (the little square denotes a right angle).

  • 90°+48°+ ∠C= 180°                               <em>Substitute values in.</em>
  • 138°+ ∠C =180°                                      <em>Add</em>  
  • 138°-138° ∠C= 180°-138°                       <em>Subtract 138 from both sides.</em>        
  • ∠C= 42°    

Note that angle C is part of another triangle. It is isosceles because the two legs (CD and CE) are congruent. Therefore, the two base angles (E and D) are congruent.

  • ∠C+∠D+∠E= 180°
  • ∠C+ 2∠D= 180°                             <em>Angles D and E are congruent</em>
  • 42°+ 2∠D= 180°                             <em>Substitute 42 in for angle C</em>
  • 42°-42° +2∠D= 180°-42°               <em>Subtract 42 from both sides.</em>
  • 2∠D=  138°
  • 2∠D/2= 138°/2                              <em>Divide both sides by 2.</em>
  • ∠D= 69°

∠D and ∠E equal 69 degrees.

Angle CED (∠E)  and DEB are on a straight line together. Therefore, they are supplementary and equal 180 degrees.

  • ∠CED+ ∠DEB= 180
  • 69° +∠DEB= 180°                    <em>Substitute 69 for angle CED</em>
  • 69°-69° +∠DEB= 180°-69°      <em>Subtract 69 from both sides</em>
  • ∠DEB=111°

Angle DEB is equal to <u>111 degrees</u>

8 0
3 years ago
Find the value of 33 - (4)(2).<br><br> 1<br> 10<br> 19&lt;<br> 46
olganol [36]

Answer:

4 into 2 gives 8

so , 33-8 = 25.

which is greater than 19 or 19 <

Step-by-step explanation:

8 0
3 years ago
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