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ZanzabumX [31]
3 years ago
11

12. A baseball player throws a ball. While the 700.0-g ball is in the pitcher’s hand, there is a force of 125 N on it. What is t

he acceleration of the ball?
Physics
1 answer:
OLEGan [10]3 years ago
7 0

Answer:

F=ma

125N=.7*a solve for a.

Explanation:

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How do you know the speed of an electromagnetic wave in a vacuum?
Ivenika [448]
The speed of electromagnetic waves in a vacuum is the same as the speed of light. It can be measured by finding the frequency and wavelength of two different waves, and then by that correlation, the speed of the waveform.
Hope this helps you (:
7 0
4 years ago
Guys help me please gr5 science pls help
Stolb23 [73]

Answer:

just google it.

Explanation:

Because its easier

7 0
4 years ago
An electric current of 200 A is passed through a stainless steel wire having a radius R of 0.001268 m. The wire is L = 0.91 m lo
denis23 [38]

Answer:

The value is   T_m  =  435.2 \  K

Explanation:

From the question we are told that  

   The  current is  I  =  200 \ A

   The radius is  R =  0.001268 \  m

   The  length of the wire is  L  =  0.91 \  m\

    The  resistance is  R  =  0.126 \  \Omega

    The  outer surface temperature is  T _o  =  422.1 \  K

    The average thermal conductivity is  \sigma  =  22.5 W/mK

   

Generally the heat generated in the stainless steel wire is mathematically represented as  

    Q =  \frac{Power}{ \pi r^2L}

     Q =  \frac{I^2 R}{ \pi r^2L}

=>   Q =  \frac{200^2 * 0.126}{3.142 *  (0.001268)^2 * 0.91}

=>   Q =  1.096*10^{9}\  W/m^3

Generally the middle temperature is mathematically represented as

      T_m  =  T_o  + \frac{Q * r^2 }{ 6  * \sigma }

       T_m  =  422.1  +  \frac{1.096*10^{-9} * 0.001268^2}{6 * 22.5}

       T_m  =  435.2 \  K

4 0
3 years ago
In general, what is true of the alpha star in a constellation?
horrorfan [7]
It is generally the brightest compared to the other stars in the constellation.
7 0
4 years ago
Which statement descThe image shows the right-hand rule being used for a current-carrying wire.
Makovka662 [10]
Answer:

The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.

Explanation:

The first figure that I copy here with is the figure corresponding to this question.

The thumb is pointing upward.

The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.

The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.

So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.

4 0
4 years ago
Read 2 more answers
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