Answer:
True
Explanation:
The force on the electron when it enters in a magnetic field is given by
F = q ( v x B)
F = -e x V x B x Sin∅
here, F is the force vector, B be the magnetic field vector and v be the velocity vector.
If the angle between the velocity vector and the magnetic field vector is 0 degree, then force is zero.
When the electrons enters in the magnetic field at any arbitrary angle, it experiences a force and hence it accelerate up.
An object with a constant pushing or pulling force is exerted on it is greater than the frictional force, than A. The object will accelerate.
Answer:
The magnitude of the magnetic field at the origin is .
Explanation:
Given :
50-A wire is in the x-z plane and is 5 m from the z axis.
Also , 40-A wire is in the y-z plane and is 4 m from the z axis.
Now , since both the wire are perpendicular to each other .
Therefore , magnetic field are also perpendicular to each other .
Magnetic field at origin due to wire 1 is :
Magnetic field at origin due to wire 2 is :
Now , therefore net magnetic field is :
Putting value of
We get ,
Therefore, the magnitude of the magnetic field at the origin is .
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If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).