Answer:
The force required to hold the contraction in place is 665.91 N ↑
Explanation:
Given;
specific gravity of oil, γ = 0.75
Volumetric flow rate, V 3.2 Ft³/s = 0.0906 m³/s
where;
is the density of oil
is the density of water = 1000 kg/m³
∴density of oil () = γ × density of water()
= 0.75 × 1000 kg/m³
= 750kg/m³
Buoyant Force = ρVg
= 750 × 0.0906 × 9.8
= 665.91 N ↑
This force acts upward or opposite gravitational force.
Therefore, the force required to hold the contraction in place is 665.91 N ↑
1) Current
2) Atoms
3) Wire
4) Negative
5) Neutron
6) Shock
7) Switch
8) Static
9) Volt
10) Battery
11) Dam
12) Thomas Edison
13) Benjamin Franklin
14) Alessandro Volta
15) Michael Faraday
I would say that these would be your correct answers, btw I'm doing something that is close to the same right now
Hope this helps :)
Answer: time is the same
Explanation: the distance(H) is the same in each case .
we drop the balls , no drag force using basic kimnematics
y =gt*t/2 , yo=0 , vo=0 , y=H , so : t= sqrt(2H/g)
comment: if distance H starts to grow....we could begin to note a difference because of gravity g is smaller as we go up
