Answer:
The internal resistance of the cell is 0.051 ohm.
Explanation:
Given;
emf of the battery, E = 12 V
terminal voltage of the cell, V = 8.2 V
current in the circuit, I = 75 A
let the potential drop of the cell due to internal resistance (r) = Ir
The internal resistance of the cell is calculated from the equation below;
E = V + Ir
where;
r is the internal resistance of the cell
Therefore, the internal resistance of the cell is 0.051 ohm.
Answer:
The value is
Explanation:
From the question we are told that
The radius of the inner conductor is
The radius of the outer conductor is
The potential at the outer conductor is
Generally the capacitance per length of the capacitor like set up of the two conductors is
Here is the permitivity of free space with value
=>
=>
Generally given that the potential of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge
Generally the line charge density of the outer conductor is mathematically represented as
=>
=>
Generally the surface charge density is mathematically represented as
here
=>
=>