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Xelga [282]
3 years ago
13

Verify the identity.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0

Answer:

from left hand side:tan^2/secx=(,sin^2x/cos^2x)/(1/cosx)=sin^2x/cosx=sinx×sinx/cosx=sinx.tanx=right hand side.verified.

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What is... X/2 - 13 = 1
kow [346]
X ÷ 2 - 13 = 1
Write the division as a fraction
\frac{1}{2}x - 13 = 1
Multiple both sides of the equation by 2
2 \times  \frac{1}{2}x  \times  - 2 \times 13 = 12
Reduce the number with greatest common divisor 2
x - 2 \times 3 = 2
Multiply the numbers
- 2 \times 13
Then u will have
x - 26 = 2
Move constant to the right by adding its opposite sides
x - 26 + 26 = 2 + 26
Eliminate the opposites
- 26 + 26
Then you have
x = 2 + 26
Add the numbers
x = 28

5 0
3 years ago
Please help me with i ii iii<br> Step by step
UkoKoshka [18]

(i) I used distributive property to get the x’s and y’s out of parentheses. I then combined like-terms to simplify until I could do no more. That is your final answer for (i) is -3x - 12y

(ii) This one is similar to the first one, just with no parentheses. I combined like terms again until not like terms were left. Your final answer for (ii) is -3k -2 -2n

(iii) I started by dividing 15 by 3 and got 5, and because the 15 had an x to it, you get 5x. I then moved onto the next term, 9. 9 divided by 3, to get 3. Your final answer for (iii) is 5x + 3

7 0
3 years ago
Read 2 more answers
{(3,5),(-2,1),(4,3),(-1,4)} is each of these relation's a function?
marysya [2.9K]

Answer:

It is not a function.

Step-by-step explanation:

{(3,5),(-2,1),(<u>4</u>,3),(-1,<u>4</u>)}

A function is a special type of relation. In a function, no two ordered pairs have the same first  component.

This relation has two 4s.

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3 years ago
Can you simplify 3/r + 7/r+3
Nutka1998 [239]
Combine the fractions by finding a common denominator. 
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I have 3 pets at home
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