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3 years ago

Determine the value of 'X

Mathematics

2 answers:

snow_lady [41]3 years ago

6 0

Answer:

x =22

Step-by-step explanation:

ABCD is a parallelogram. In parallelogram, adjacent angles are supplementary.

∠B +∠C = 180

4x + 12 + 3x + 14 = 180

Combine like terms

4x +3x + 12+ 14 = 180

7x + 26 = 180 {Subtract 26 from both sides}

7x = 180 - 26

7x = 154 {Divide both sides by 7}

x = 154/7

x = 22

Nikolay [14]3 years ago

4 0

Answer:

x=22° hope it helps:)

Step-by-step explanation:

Please mark it the brainliest if you won't mind:)

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ki77a [65]

Wait. Hold on a moment.

8 0

3 years ago

Is the line that contains the points (3,5) and

sdas [7]

m₁ ≠ -1/m₂

So, the lines, line 1 and line 2 are not perpendicular.

Step-by-step explanation:

For finding if the two lines are perpendicular, we will find the slope of two lines and if slope of line 1= -1/slope of line 2 then the lines are perpendicular

Finding slope of line 1 (m₁)

line 1 that contains the points (3,5) and (-3,3)

$slope = \frac{y_{2}-y_{1}}{x{2}-x_{1}} \\Where\,\, y_{2}=3,y_{1}=5,x{2}=-3,x_{1}=3\\slope =\frac{3-5}{-3-3}\\slope=\frac{-2}{-6}\\slope=\frac{1}{3}$

So, $m_{1}=\frac{1}{3}$

Finding slope of line 2 (m₂)

$slope = \frac{y_{2}-y_{1}}{x{2}-x_{1}} \\Where\,\, y_{2}=4,y_{1}=5,x_{2}=-4,x_{1}=2\\slope =\frac{4-5}{-4-2}\\slope=\frac{1}{-6}\\slope=-\frac{1}{6}$

So, $m_{2}=\frac{1}{6}$

Since, m₁ ≠ -1/m₂

So, the lines, line 1 and line 2 are not perpendicular.

Keywords: Perpendicular lines

Learn more about Linear Equation at:

#learnwithBrainly

3 0

3 years ago

Solve 6y = 24 – 3x for y in terms of x.

olchik [2.2K]

6y = 24 -3x
divide both sides by 6.
y = (x)/2 +4

5 0

3 years ago

I have to write at least 20 character for it to let me post

Archy [21]

Answer:

Choice #4 is the most likely fit.

4 0

3 years ago

How to find h’(3) <br> base on the graph

const2013 [10]

By the quotient rule for differentiation,

$\displaystyle h'(x) = \dfrac{g(x)f'(x) - f(x)g'(x)}{g(x)^2}$

According to the plots of $f$ and $g$ , we have $f(3)=2$ and $g(3)=3$ .

On the interval [2, 4], $f$ is a line through the points (2, 5) and (4, -1), and hence has slope (-1 - 5)/(4 - 2) = -3, so $f'(3)=-3$ . We can similarly find $g'(3)=2$ .

Then

$h'(3) = \dfrac{3\cdot(-3)-2\cdot2}{3^2} = \boxed{-\dfrac{13}9}$

4 0

2 years ago