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3 years ago

??????????????????????????????????????????????

Chemistry

2 answers:

mina [271]3 years ago

8 0

Answer:

a = ureter

b = Urethra

C = Bladder

d = kidney

Elanso [62]3 years ago

7 0

Answer:

A = Ureter

Small amounts of urine flow from the ureters into the bladder

B = Urethra

The Urethra is the tube that carries urine from the bladder to outside the body

C = Urinary Bladder

Stores Urine

D = Kidney

remove wastes and extra fluid from your body.

-TheUnknownScientist

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How many grams of RbOH are present in 35.0 mL of a 5.50 M RbOH solution?

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I think 5.50 M x 35.0 mL x molar mass of RbOH = mass (g)

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4 years ago

Carbon dioxide enters the atmosphere by natural processes and from human activity. Why is the latter a cause of concern?

Angelina_Jolie [31]

By removing long-buried fossil fuels and burning them to produce electricity, human activities have drastically disrupted the natural carbon cycle and released CO2 into the atmosphere. The burning of fossil fuels like coal, natural gas, and oil, including gasoline, is responsible for 85% of all human-produced carbon dioxide emissions.

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2 years ago

When balanced, which equations would have the coefficient 3 in front of the first set of atoms? Check all that apply. A. AgBr +

masha68 [24]

Balancing the choices, we have as follows:

A. 3AgBr + GaPO4 → Ag3PO4 +GaBr3

B. 3H2SO4 + 2B(OH)3 → B2(SO4)3 + 6H2O

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4 years ago

A compound is 7.74% hydrogen and 92.26% carbon by mass. At 100°C a 0.6883 g sample of the gas occupies 250 mL when the pressure

ycow [4]

Answer: The molecular formula for the compound is $C_6H_6$

Explanation:

We are given:

Percentage of C = 92.26 %

Percentage of H = 7.74 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 92.26 g

Mass of H = 7.74 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{92.26g}{12g/mole}=7.68moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{7.74g}{1g/mole}=7.74moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.68 moles.

For Carbon = $\frac{7.68}{7.68}=1$

For Hydrogen = $\frac{7.74}{7.68}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is $CH$

Calculating the molar mass of the compound:

To calculate the molecular mass, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{m}{M}RT$

where,

P = pressure of the gas = 820 torr

V = Volume of gas = 250 mL = 0.250 L (Conversion factor: 1 L = 1000 mL )

m = mass of gas = 0.6883 g

M = Molar mass of gas = ?

R = Gas constant = $62.3637\text{ L. torr }mol^{-1}K^{-1}$

T = temperature of the gas = $100^oC=(100+273)K=373K$

Putting values in above equation, we get:

$820torr\times 0.250L=\frac{0.6883g}{M}\times 62.3637\text{ L torr }mol^{-1}K^{-1}\times 373K\\\\M=\frac{0.6883\times 62.3637\times 373}{820\times 0.250}=78.10g/mol$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 78.10 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

$n=\frac{78.10g/mol}{13g/mol}=6$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 6)}H_{(1\times 6)}=C_6H_6$

Hence, the molecular formula for the compound is $C_6H_6$

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3 years ago

The cation of the salt is sodium ion, and the anion is aurothiosulfate ion. Based on the chemical formula of the salt, what must

marta [7]

Answer:

Explanation:

Sodium aurothiosulfate is a salt with the formula Na₃Au(S₂O₃)₂. The cation of the salt is sodium ion, and the anion is aurothiosulfate ion. We can determine the charge of the aurothiosulfate ion, considering that the sum of the positive and negative charges must be equal to the charge of the compound, which is zero.

3 × Na⁺ + 1 × Au(S₂O₃)₂ⁿ⁻ = 0

3 × +1 + 1 × Au(S₂O₃)₂ⁿ⁻ = 0

Au(S₂O₃)₂ⁿ⁻ = 3-

7 0

3 years ago