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marusya05 [52]
4 years ago
15

If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a

Chemistry
1 answer:
Vinil7 [7]4 years ago
7 0
If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a TETRAHEDRAL GEOMETORY
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Write its IUPAC name?​
Liono4ka [1.6K]

Answer:

Hello

please make sure that there is any group which is join with alkane

6 0
3 years ago
Write a half-reaction for the oxidation of the manganese in MnCO3(s) to MnO2(s) in neutral groundwater where the carbonate-conta
Sergeu [11.5K]

Answer:

The half-reaction for the oxidation of the manganese in MnCO_3(s) to MnO_2(s).:

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+

Explanation:

MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Let us say the medium in which reaction is taking place is an acidic medium. And balancing in an acidic mediums done as;

Step 1: Balance all the atom beside oxygen and hydrogen atom;

MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Manganese and carbon are balanced.

Step 2: Balance oxygen atom adding water on the required side:

MnCO_3+H_2O+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Step 3: Now balance hydrogen atom by adding hydrogen ion on the required side:

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+

6 0
3 years ago
How many acetone molecules are in a bottle of acetone with a volume of 445 mL ? (density of acetone = 0.788 g/cm3).
Mkey [24]
<h2>Hello!</h2>

The answer is: 3.63x10^{24}particles

<h2>Why?</h2>

First, we need to calculate the molecular weight of the acetone (CH3COCH3)

So,

C=12.011g/mol\\O=15.99g/mol\\H=1.008g/mol

Then,

CH3COCH3=12.011+(1.008)*3+12.011+15.999+12.011+(1.008)*3=58.08g/mol

Second, we need to calculate the mass of the acetone in the bottle

We need to remember that 1cm^{3}=1mL

So,

445cm^{3}*\frac{0.788g}{cm^{3}}=350.66g

Third, we need to calculate the number of moles:

350.66g*\frac{1mol}{58.08g}=6.03moles

Fourth, we need to calculate the number of atoms:

Remember, 1 mol=6.022x10^{23}particles

Therefore,

6.03moles*\frac{6.022x10^{23}particles }{1mol}=3.63x10^{24}particles

Have a nice day!

4 0
4 years ago
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What do you notice about the relationship between the force strength and the size of the velocity change?
ella [17]

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a mass is constant during -free-weight training,a greater impulse will result in greater velocity.therefore as a generation of force greater than weight of the resistance increases.

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Isabel pushes a toy car, giving it kinetic energy. When this happens, what happens to the energy in her arm?
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c the energy in her arn decrease

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