Answer:
3–methyl–2–butanol
Explanation:
To name the compound, we must:
1. Identify the functional group.
2. Give the functional group of the compound the lowest possible count.
3. Locate the longest continuous carbon chain. This gives the parent name of the compound.
4. Identify the substituent group attached.
5. Give the substituent group the lowest possible count.
6. Combine the above to get the name of the compound.
Now, let us obtain the name of the compound.
1. The functional group of the compound is Alcohol i.e —OH.
2. The functional group is located at carbon 2.
3. The longest continuous carbon chain is carbon 4 i.e butane. But the presence of the functional group i.e OH will replace the –e in butane with –ol. Therefore, the compound is butanol.
4. The substituent group attached is methyl i.e CH3.
5. The substituent group is located at carbon 3.
6. Therefore, the name of the compound is:
3–methyl–2–butanol.
Answer:
The above reaction is an example of <u>alcoholic fermentation</u>.
Explanation:
In alcoholic fermentation, one mole of glucose gets converted into two moles of alcohol, two moles of carbon dioxide and two moles of adenosine tri-phosphate (ATP).
Answer:
see explaination
Explanation:
We are given the (R)-3-bromo-2,3-dimethylpentane and asking to draw the curved arrow which is the showing the mechanism for first-order substitution and first-order elimination reactions. We know the formation of carbocation is the rate determining step in the first-order substitution and first-order elimination reactions.
So in the (R)-3-bromo-2,3-dimethylpentane there is –Br gets removed and formed the tertiary carbocation which is more stable, so the curved arrows in Box 1 to depict the flow of electrons and intermediate in Box 2.
Check attachment
Answer:
Liquids, because they flow, can occupy whatever shape their container has, so they do not have a fixed shape. Because the particles in liquids are very close together (barely further apart than in solids) liquids do not easily compress, so their volume is fixed. hope that helps love!
Answer:
1.0 x 10⁻⁸ M.
Explanation:
<em>∵ [H⁺][OH⁻] = 10⁻¹⁴.
</em>
∵ [H⁺] = 100 [OH⁻].
∴ 100 [OH⁻][OH⁻] = 10⁻¹⁴.
∴ 100 [OH⁻]² = 10⁻¹⁴.
[OH⁻]² = 10⁻¹⁴/ 100 = 1.0 x 10⁻¹⁶.
<em>∴ [OH⁻] = √(1.0 x 10⁻¹⁶) = 1.0 x 10⁻⁸ M.
</em>
