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likoan [24]
3 years ago
10

A solution is 5.00% potassium chloride by mass. How much potassium chloride would you expect to collect by evaporating 150.0 g o

f the solution?

Chemistry
1 answer:
stepan [7]3 years ago
8 0

Answer:

C. 7.50g

Explanation:

The percent (%) by mass of a solute in a solution refers to the number of grams contained in 100g of solution by that solute. In this case, 5% by mass of pottasium chloride (KCl) means 5g of KCl is contained in 100g of solution.

Therefore, in 150g of solution, there would be:

5g/100g × 150g

= 0.05 × 150

= 7.50g of KCl solute.

Hence, 7.50g of pottasium chloride would be expected to be collected by evaporating 150.0 g of the solution.

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What is the total energy required to break all the bonds in 1 mol propanol,<br> C3H8O?
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Answer:

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Explanation:

We note that propanol, C₃H₈O is also known as 1-propanol is written as follows;

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CH₃-CH₂-CH₂-OH

Hence, the total number of bonds are;

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C-C Bonds = 2

The bond energies are as follows;

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O-H Bond = 468 kJ/mol

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Energy required to break the bonds in 1-propanol is therefore;

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C-O Bonds = 358 kJ/mol × 1 = 358 kJ/mol

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The total energy to break all the bonds in 1 mole of 1-propanol = 4411 kJ/mol.

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4 years ago
A gas occupies 40.0 mL at 150 K. What volume does it occupy at 300 K,
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Answer:

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3 years ago
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Answer:

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