) how much of the primary standard benzoic acid (fm 122.12, density 1.27 g/ml) should you weigh out to obtain a 100.0 mm aqueous
1 answer:
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<u>Answer:</u> The amount of heat released is -7.203 kJ
<u>Explanation:</u>
The given chemical equation follows:
To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:
When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ
So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be
- To calculate the number of moles, we use the equation:
Given mass of hydrogen peroxide = 2.50 g
Molar mass of hydrogen peroxide = 34 g/mol
Putting values in above equation, we get:
- To calculate the heat of the reaction, we use the equation:
where,
= amount of heat released
n = number of moles = 0.0735 moles
= enthalpy change of the reaction = -98 kJ/mol
Putting values in above equation, we get:
Hence, the amount of heat released is -7.203 kJ
Answer:
The total kg from the mixer:
Evaporated water:
Jam produced:
Explanation:
Step by step:
1) Kg of mixture from the mixer
It says that crushed fruit is added to the mixer with the sugar and pectin.
The fruit added is 1000 kg
The sugar added is 1.22 kg sugar/1 kg crushed fruit:
The pectin added is 0.0025 kg pectin/1 kg crushed fruit:
The total kg from the mixer:
2) Evaporated water
To calculate the evaporated water it's important to have in mind that the mix goes from a concentration of 14 wt% to 67 wt%. This difference is because of the evaporated water. So:
Initial: 1000 kg of fruit with 14 wt% of solids
<em>This amount of solids is constant </em>
Final: The mass of solids is the same but now it represents the 67 wt%
and
3) Jam produced