Let g(x) = 9x + 24<br> find g(3)<br> Let g(x)=9x+24, find g(3).

Heyy besties can ya'll please help me with 1 to 4 im really left behind

hram777 [196]

Answer:

1st one: 360

2nd one: 260

3rd one: 210

4th one: 72

Step-by-step explanation:

here are the actual answers since the other person who "answered" is clearly just hungry for points

7 0

3 years ago

The germination rate is the rate at which plants begin to grow after the seed is planted.

chubhunter [2.5K]

Answer:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

$\hat p=\frac{7}{15}=0.467$ estimated proportion of seeds germinated

$p_o=0.9$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:

Null hypothesis: $p\geq 0.9$

Alternative hypothesis: $p < 0.9$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0

3 years ago

Plz help..................refresh page before u answer

S_A_V [24]

$\dfrac{7}{x^2-36}-\dfrac{1}{x-6}=\dfrac{7}{(x+6)(x-6)}-\dfrac{1}{x-6}=\\\\\\=
\dfrac{7}{(x+6)(x-6)}-\dfrac{(x+6)}{(x+6)(x-6)}=\dfrac{7-x-6}{(x+6)(x-6)}=\boxed{\dfrac{1-x}{(x+6)(x-6)}}$

Answer B.

8 0

3 years ago

223×5<br><img src="https://tex.z-dn.net/?f=223%20%5Ctimes%205%20%20%3D%20" id="TexFormula1" title="223 \times 5 = " alt="223 \t

ivann1987 [24]

The answer is 1115 just multiply or use calculator

4 0

4 years ago

Read 2 more answers

Need to turn this in asap

OleMash [197]

Between two consecutive numbers 5 and 6 √34 is.

Here we have to find the two whole numbers, between which √34 is.

√25 = 5 and √36 = 6

25 < 34 < 36

Now taking root, we have

√25 < √34 < √36

5 < √34 < 6

Since √25 =5 and √36 = 6, it is known that √34 is between 5 and 6.

To know more about the roots refer to the link given below:

brainly.com/question/776122

#SPJ9

3 0

1 year ago

Let g(x) = 9x + 24 find g(3) Let g(x)=9x+24, find g(3).