1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexdok [17]
2 years ago
10

HELPPPP PLSSSS IT'S UNIT RATE BUT I Don't HAVE MUCH TIME TO DO IT!!!​

Mathematics
1 answer:
horsena [70]2 years ago
4 0

Answer:

So Jennys Jean store charges the higher rate.

Step-by-step explanation:

Jeanys Jean store

Cost/pair = 20/1 = $20 per pair

Jeans warehouse

Cost/pairs = 36/2 = $18 per pair

So Jennys Jean store charges the higher rate.

You might be interested in
2x+5y=-11. <br> -8x-5y=-11
MissTica
2x+5y=-11 slope is -2/5, y- intercept is -11/5
-8x-5y=-11 slope is -8/5, y- intercept is 11/5
3 0
2 years ago
Read 2 more answers
Use the system of equations to answer the questions.
Mrac [35]

Answer:

the value of x and y is 3 and -1 respectively.

Step-by-step explanation:

from the question

let

2x + 3y = 3........................ equation 1

y = 8 - 3x.............................. equation 2

put y = 8 - 3x in equation 1

2x + 3y = 3........................ equation 1

2x + 3 ( 8 - 3x) = 3

2x + 24 - 9x = 3

24 - 7x = 3

24  = 3 + 7x

24 -3 = 7x

21 = 7x

divide both sides by 7

x = 3

put x = 3 in equation 2

y = 8 - 3x.............................. equation 2

y = 8 - 3 ( 3)

y = 8 -9

y = -1

therefore the value of x and y is 3 and -1 respectively.

3 0
3 years ago
The distance between two stations is 540 km. A train takes 3 hours to
mihalych1998 [28]
180 km/hr
50 m/s
Here’s the work

8 0
2 years ago
Three times the sum of a number and seven is two less than five times the number
damaskus [11]
The answer for x is 1/13
5 0
3 years ago
Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}&#10;

                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}&#10;

                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}&#10;

                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
3 years ago
Other questions:
  • I'm Stuck on this problem
    6·1 answer
  • What is 2/5÷4 i need help on my khann
    8·2 answers
  • The model below represents the equation 4a = -20
    6·1 answer
  • Please solve this question​
    12·1 answer
  • Help with number 10.
    9·1 answer
  • How to do it this question
    6·1 answer
  • Common facer of 50,30,100
    5·1 answer
  • What inequality is represented by this graph?​
    13·1 answer
  • Find the probability of drawing an ace and a king in either order
    9·1 answer
  • Area of the rectangle is 126 sqaure meters. Length of the rectangle is 4 more than 2 times its width. Find length and width of t
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!